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chase

  • 5 years ago

does anybody know how to do trig?

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  1. chase
    • 5 years ago
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    sin3x=3sinx??

  2. anonymous
    • 5 years ago
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    sin3x = sin(2x+x) use sin(a+b) formula.

  3. chase
    • 5 years ago
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    what do you do with it from this point? sin2xcosx+cos2xsinx=3sinx

  4. anonymous
    • 5 years ago
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    sin2x = sin(x+x) and cos2x = cos (x+x)

  5. chase
    • 5 years ago
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    I'm sorry but I'm still stuck as what I'm supposed to do with this. I put in the trig identities but after I had cancled out things and such I ended up with sinx+cosx which I'm sure is wrong

  6. anonymous
    • 5 years ago
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    you are supposed to get everything in terms of sin x. then you can substitute sinx = y and solve for y in a cubic equation and substitute back into sinx to find x.

  7. chase
    • 5 years ago
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    so would it work if I changed sinx+cosx to sinx(1-sinx)?

  8. anonymous
    • 5 years ago
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    I am just giving you the outline of what you need to do. I haven't solved it myself.

  9. chase
    • 5 years ago
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    well your insight has been most insightful, but I am hopeless a this stuff

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