A community for students.
Here's the question you clicked on:
 0 viewing
chase
 5 years ago
does anybody know how to do trig?
chase
 5 years ago
does anybody know how to do trig?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin3x = sin(2x+x) use sin(a+b) formula.

chase
 5 years ago
Best ResponseYou've already chosen the best response.0what do you do with it from this point? sin2xcosx+cos2xsinx=3sinx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin2x = sin(x+x) and cos2x = cos (x+x)

chase
 5 years ago
Best ResponseYou've already chosen the best response.0I'm sorry but I'm still stuck as what I'm supposed to do with this. I put in the trig identities but after I had cancled out things and such I ended up with sinx+cosx which I'm sure is wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you are supposed to get everything in terms of sin x. then you can substitute sinx = y and solve for y in a cubic equation and substitute back into sinx to find x.

chase
 5 years ago
Best ResponseYou've already chosen the best response.0so would it work if I changed sinx+cosx to sinx(1sinx)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am just giving you the outline of what you need to do. I haven't solved it myself.

chase
 5 years ago
Best ResponseYou've already chosen the best response.0well your insight has been most insightful, but I am hopeless a this stuff
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.