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anonymous
 5 years ago
Hello! Not quite sure about how to find derivative of:
y = 3x  5cos('pi'x)^2
anonymous
 5 years ago
Hello! Not quite sure about how to find derivative of: y = 3x  5cos('pi'x)^2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03x prime=3, 5cos(u)^2= 10sin(u)*u prime= 3+10sin(pi*x)*pi

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y'=35*2*cos(pi*x)*pi*(sin(pi*x))=3+5pi*sin(2pix)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dellcom, you forgot that (cos^2)'=2cos*(sin).... :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK, so I use the chain use. But I'm still missing something. The answer I get is: \[y = 3 + 10\cos \pi x \sin \pi x\] Its seems like you combined something that I am not seeing..
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