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anonymous
 5 years ago
How to solve system of quadratic linear equations algebraically with y=3x+12 and y=x22x18?
anonymous
 5 years ago
How to solve system of quadratic linear equations algebraically with y=3x+12 and y=x22x18?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0substitute y as 3x+12 in the second equation and solve for x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes sorry, I meant, when you're trying to find out the plotting points, the number pair, what do you do?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0They are both written as y = ... So knowing that y = y, the other sides are equal to each other too, so set the other sides equal to each other: 3x + 12 = x^22x18

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0...Then solve for x, and once you know x, use the simpler equation to find y.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you find out x and y. then you plotting poitns are (x,y)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know what you mean, because there is only only point (x,y) or at most two, which satisfies both these equations. You have to find that point by substituting the first equation in the second equation.
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