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anonymous

  • 5 years ago

A 30 ft piece of rope is cut into three sections such that the length of the second section is one ft more than the first section and the length of the third section is one ft less than three times the first. Find the lengths of the three sections......please help.

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  1. anonymous
    • 5 years ago
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    say the length of the first section is L ft. long. what can you tell me about the lengths of section 2 and section 3?

  2. anonymous
    • 5 years ago
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    The way you begin is to decide which section gets x. In the first sentence you see the length of the second section is..... and the length of the third section is..... YOU NEVER SEE the length of the first section is.... so that is the section that gets the "x"

  3. anonymous
    • 5 years ago
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    Thats all the problem says.....where do I begin?

  4. anonymous
    • 5 years ago
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    first section = x second section = x + 1 (one foot more than the first section) third section = 3x - 1 ( one foot less than three times the first section)

  5. anonymous
    • 5 years ago
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    If you add the three sections together you get the entire rope which is 30 ft.

  6. anonymous
    • 5 years ago
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    So x + x + 1 + 3x - 1 = 30

  7. anonymous
    • 5 years ago
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    Add like terms. 5x = 30 (x + x + 3x = 5x and 1 - 1 = 0)

  8. anonymous
    • 5 years ago
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    I follow...

  9. anonymous
    • 5 years ago
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    5x = 30 x = 6 Divide by 5 on both sides.

  10. anonymous
    • 5 years ago
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    ok

  11. anonymous
    • 5 years ago
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    first section = x which is 6ft second section = x + 1 which is 6 + 1 = 7 ft. third section = 3x - 1 which is 3(6) - 1 = 18 - 1 = 17 ft. 6 + 7 + 17 = 30 ft.

  12. anonymous
    • 5 years ago
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    ok :) thanks so very much!

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