anonymous
  • anonymous
A 30 ft piece of rope is cut into three sections such that the length of the second section is one ft more than the first section and the length of the third section is one ft less than three times the first. Find the lengths of the three sections......please help.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
say the length of the first section is L ft. long. what can you tell me about the lengths of section 2 and section 3?
anonymous
  • anonymous
The way you begin is to decide which section gets x. In the first sentence you see the length of the second section is..... and the length of the third section is..... YOU NEVER SEE the length of the first section is.... so that is the section that gets the "x"
anonymous
  • anonymous
Thats all the problem says.....where do I begin?

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More answers

anonymous
  • anonymous
first section = x second section = x + 1 (one foot more than the first section) third section = 3x - 1 ( one foot less than three times the first section)
anonymous
  • anonymous
If you add the three sections together you get the entire rope which is 30 ft.
anonymous
  • anonymous
So x + x + 1 + 3x - 1 = 30
anonymous
  • anonymous
Add like terms. 5x = 30 (x + x + 3x = 5x and 1 - 1 = 0)
anonymous
  • anonymous
I follow...
anonymous
  • anonymous
5x = 30 x = 6 Divide by 5 on both sides.
anonymous
  • anonymous
ok
anonymous
  • anonymous
first section = x which is 6ft second section = x + 1 which is 6 + 1 = 7 ft. third section = 3x - 1 which is 3(6) - 1 = 18 - 1 = 17 ft. 6 + 7 + 17 = 30 ft.
anonymous
  • anonymous
ok :) thanks so very much!

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