find the equation of the tangent line to the curve when x has the given value... f(x)= 5x^2+x ; x=-4

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find the equation of the tangent line to the curve when x has the given value... f(x)= 5x^2+x ; x=-4

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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You have to find the gradient function of f first. This will give you the gradient at any point. Then you need to use the point-gradient formula for a straight line. The point you'll be using is the point where the tangent touches the parabola (since a tangent only touches at one point). So the point here is x=-4, f(-4) = 5(-4)^2+(-4) = 76; i.e (-4,76). Your gradient is \[f'(x)=10x+1 \rightarrow f'(-4)=-40+1 = -39\]The equation of the tangent line is then\[y-76=-39(x-(-4)) \rightarrow y = -39x-80\]
Re-check everything - I just saw this question unanswered and stole some time. The theory is right, though :)
yeah that's right thank u:) i just couldnt figure out the steps

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