## anonymous 5 years ago What is the y intercept of x/7-4y=-2

1. anonymous

rearrange the equation into general form of straight line, y=mx+c which c is the y-intercept.

2. anonymous

How do you write this in standard form?

3. anonymous

x/7-4y=-2, -4y=-2- x/7, y=1/2 + x/28.

4. anonymous

I would put it in standard form by first multiplying both sides of the equation by 7 to get rid of the denominator in the first term: x/7 That would be $(\frac{x}{7}-4y)*7 = -2*7$ then distributing on the left you get $\frac{x}{7}*7-4y*7 = -2*7$ which is $\frac{x}{7}*\frac{7}{1}-4y*7 = -2*7$ and the first term reduces to x since the 7's cancel so you get $x-28y=-14$ Now isolate y on one side of the equation by putting all the terms without y on the other and dividing each term by -28

5. anonymous

$x-28y=-14$ -x -x $\frac{-28y}{-28}=\frac{-x}{-28}-\frac{14}{-28}$ $\frac{-28y}{-28}=\frac{-x}{-28}+\frac{-14}{-28}$ which simplifies to $y=\frac{x}{28}+\frac{1}{2}$ c is $\frac{1}{2}$ Does that help? :)