anonymous
  • anonymous
What is the y intercept of x/7-4y=-2
Mathematics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
rearrange the equation into general form of straight line, y=mx+c which c is the y-intercept.
anonymous
  • anonymous
How do you write this in standard form?
anonymous
  • anonymous
x/7-4y=-2, -4y=-2- x/7, y=1/2 + x/28.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I would put it in standard form by first multiplying both sides of the equation by 7 to get rid of the denominator in the first term: x/7 That would be \[(\frac{x}{7}-4y)*7 = -2*7\] then distributing on the left you get \[\frac{x}{7}*7-4y*7 = -2*7\] which is \[\frac{x}{7}*\frac{7}{1}-4y*7 = -2*7\] and the first term reduces to x since the 7's cancel so you get \[x-28y=-14\] Now isolate y on one side of the equation by putting all the terms without y on the other and dividing each term by -28
anonymous
  • anonymous
\[x-28y=-14 \] -x -x \[\frac{-28y}{-28}=\frac{-x}{-28}-\frac{14}{-28}\] \[\frac{-28y}{-28}=\frac{-x}{-28}+\frac{-14}{-28}\] which simplifies to \[y=\frac{x}{28}+\frac{1}{2}\] c is \[\frac{1}{2}\] Does that help? :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.