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anonymous
 5 years ago
how do you find the slope of the line tangent to the curve at the point where x=3 using the curve x=e^t and y=te^t
anonymous
 5 years ago
how do you find the slope of the line tangent to the curve at the point where x=3 using the curve x=e^t and y=te^t

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Find the derivative of <e^t, te^t>

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer is supposed to be .011 i tried dy/dt over dx/dt and plugged in 3 but kept getting it wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The line is the original vector evaluated at the point + the derivative vector evaluated at the point.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what would that look like?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nevermind figured it out thanks for the help
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