anonymous
  • anonymous
(x+1)^2+8(y+3)=0 find the vertex focus and directrix of the parabola
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
(x+1)^2+8(y+3)=0 vertex is at (-1, -3)
anonymous
  • anonymous
for the line of symmetry, i.e. just the line passing through that vertex, i.e. x= -1
anonymous
  • anonymous
how did figuring dis out

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