A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
125x^4 y^5
() ^2
5x^6 y^5
anonymous
 5 years ago
125x^4 y^5 () ^2 5x^6 y^5

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You need to take the (126x^4y^5)^2 first.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first line is y^3 sorry...not 5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is the problem (125x^4y3)^2  5x^6y^5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK.. order of operations says to ^2 first so (125x^4y^3)^2 is 125*125 = 15625 x^8y^6 (multiply exponents when you take a power to a power)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.015625x^8y^6  5x^6y^5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03125x^2y^1 you divide 15626/5 = 3125 you subtract exponents x^(86) x^2 and y^(6  5) y^1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can't have a negative exponent so you put the y term on the bottom to the positive power 3125x^2  y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k, so this is the answer? Thanks for your help!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can u help me with one more....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y^6 Z^0  y^3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y^6 z^0  y^3 first of all anything to the 0 power is equal to 1 y^6 (1)  y^3 y^6  y^3 you subtract exponents ... be careful... it is top minus bottom. so y^(6  3) so y^(6 + 3) so y^3 but because we can't have a negative exponent. it is 1  y^3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Great!! I get it. Thanks a million!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.