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anonymous

  • 5 years ago

125x^4 y^-5 (------------) ^2 5x^6 y^-5

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  1. anonymous
    • 5 years ago
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    You need to take the (126x^4y^-5)^2 first.

  2. anonymous
    • 5 years ago
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    Sorry 125

  3. anonymous
    • 5 years ago
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    first line is y^-3 sorry...not -5

  4. anonymous
    • 5 years ago
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    Is the problem (125x^4y-3)^2 ------------ 5x^6y^-5

  5. anonymous
    • 5 years ago
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    yes :)

  6. anonymous
    • 5 years ago
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    OK.. order of operations says to ^2 first so (125x^4y^-3)^2 is 125*125 = 15625 x^8y^-6 (multiply exponents when you take a power to a power)

  7. anonymous
    • 5 years ago
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    15625x^8y^-6 ------------- 5x^6y^-5

  8. anonymous
    • 5 years ago
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    ok I follow

  9. anonymous
    • 5 years ago
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    3125x^2y^-1 you divide 15626/5 = 3125 you subtract exponents x^(8-6) x^2 and y^(-6 - -5) y^-1

  10. anonymous
    • 5 years ago
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    You can't have a negative exponent so you put the y term on the bottom to the positive power 3125x^2 -------- y

  11. anonymous
    • 5 years ago
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    k, so this is the answer? Thanks for your help!!!

  12. anonymous
    • 5 years ago
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    yes

  13. anonymous
    • 5 years ago
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    can u help me with one more....

  14. anonymous
    • 5 years ago
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    y^-6 Z^0 -------- y^-3

  15. anonymous
    • 5 years ago
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    y^-6 z^0 -------- y^-3 first of all anything to the 0 power is equal to 1 y^-6 (1) ---- y^-3 y^-6 ---- y^-3 you subtract exponents ... be careful... it is top minus bottom. so y^(-6 - -3) so y^(-6 + 3) so y^-3 but because we can't have a negative exponent. it is 1 -- y^3

  16. anonymous
    • 5 years ago
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    Great!! I get it. Thanks a million!

  17. anonymous
    • 5 years ago
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    No problem.

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