anonymous
  • anonymous
125x^4 y^-5 (------------) ^2 5x^6 y^-5
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
You need to take the (126x^4y^-5)^2 first.
anonymous
  • anonymous
Sorry 125
anonymous
  • anonymous
first line is y^-3 sorry...not -5

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anonymous
  • anonymous
Is the problem (125x^4y-3)^2 ------------ 5x^6y^-5
anonymous
  • anonymous
yes :)
anonymous
  • anonymous
OK.. order of operations says to ^2 first so (125x^4y^-3)^2 is 125*125 = 15625 x^8y^-6 (multiply exponents when you take a power to a power)
anonymous
  • anonymous
15625x^8y^-6 ------------- 5x^6y^-5
anonymous
  • anonymous
ok I follow
anonymous
  • anonymous
3125x^2y^-1 you divide 15626/5 = 3125 you subtract exponents x^(8-6) x^2 and y^(-6 - -5) y^-1
anonymous
  • anonymous
You can't have a negative exponent so you put the y term on the bottom to the positive power 3125x^2 -------- y
anonymous
  • anonymous
k, so this is the answer? Thanks for your help!!!
anonymous
  • anonymous
yes
anonymous
  • anonymous
can u help me with one more....
anonymous
  • anonymous
y^-6 Z^0 -------- y^-3
anonymous
  • anonymous
y^-6 z^0 -------- y^-3 first of all anything to the 0 power is equal to 1 y^-6 (1) ---- y^-3 y^-6 ---- y^-3 you subtract exponents ... be careful... it is top minus bottom. so y^(-6 - -3) so y^(-6 + 3) so y^-3 but because we can't have a negative exponent. it is 1 -- y^3
anonymous
  • anonymous
Great!! I get it. Thanks a million!
anonymous
  • anonymous
No problem.

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