I have a test tomorrow and I don't know a single thing. Please, for the love of God, help me. Factor:
1) 125x^3-8 2) 2x^3+54
3) -2X^3-4x^2-3x-6 4) 6x^5-51x^3-27x
Stacey Warren - Expert brainly.com
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1) 125= 5*5*5=5^3; 8=2*2*2
so, 125x^3-8=5^3 *x^3 - 2^3
something like this...?
Well.. because I love God... I will help you.
1) is the difference of 2 cubes.
125x^3 - 8 you need to write each term as ( )^3
(5x)^3 - (2)^3
You have to learn this formula... no other way about it.....
(5x - 2)(25x^2 + 10x + 4) Here is how you get that answer.
Look what is in the ( )'s under the problem (5x) and (2) the first thing you do is
(5x - 2) you put what is in those ( )'s with the sign of the problem.
2nd. You use the (5x) and the (2)
(square the (5x) opposite sign of the problem you take (5x)(2) always a + sign square the(2))
(25x^2 + 10x + 4)
so you have (5x - 2)(25x^2 + 10x + 4)
2. 2(x^3 + 27) once again you can write each term as ( )^3
2((x)^3 + (3)^3) so..
we are going to use the (x) and the (3)
(x + 3) (x sign of problem 3)
(x^2 + 3x + 9) (square x, opposite sign of problem (x)(3) always a + square(3))
2(x + 3)(x^2 + 3x + 9)
-2x^3 - 4x^2-3x - 6
first two terms have a greatest common factor of -2x^2
-2x^2(x + 2)
the last two terms have a greatest common factor of -3
-3(x + 2)
-2x^2(x + 2) - 3(x + 2)
Both terms have a (x + 2) so you factor it out.
(x + 2)((-2x^2 - 3)