anonymous
  • anonymous
for n belongs to N 2^3n-7n-1 is divisible by
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
So your question is to find factors for: \[2^{3n}-7n-1?\]
anonymous
  • anonymous
yaa
anonymous
  • anonymous
Itself and 1

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anonymous
  • anonymous
hw
anonymous
  • anonymous
\[2^3 n-7 n-1\text{=}n-1 \]
anonymous
  • anonymous
noooooo it is 2^(3n)-7n-1
anonymous
  • anonymous
Sorry. 2^3n incorrect.

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