A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

show that the equation has a root in the given interval 3x^3-2x^2+5x+4=0 [-1,0]

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so use the intermediate value theorem. at -1, the function = -6. at 0, the function = 4. since the function is continuous, it must pass the x-axis in the interval -1 to 0. at that point, you have the root. hope this is helpful

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    3(-1)^3 - 2(-1)^2 + 5(-1) + 4 3(-1) - 2(1) - 5 + 4 -3 -2 -5 + 4 -6 3(0)^3 - 2(0)^2 + 5(0) + 4 3(0) -2(0) + 0 + 4 0 + 0 + 0 + 4 4 because at x = -1 , y = -6 and at x = 0, y = 4 the graph had to cross the x axis so there must be a root there.

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.