## anonymous 5 years ago differentiate 2sin^2x + sin2x^2

1. anonymous

correction: sin^2(2x) + sin2x^2

2. anonymous

so you're saying $\sin^2(2x)+\sin(2*x^2)$ or is it $\sin^2(2x)+\sin((2x)^2)$ ?

3. anonymous

the first one

4. anonymous

ok then you can also write it like: $(\sin(2x))^2+\sin(2x^2)$ and use the chain rule for differentiation in both terms: The derivative of the first term is $2(\sin(2x))^1*\cos(2x)*2$ The derivative of the second term is $\cos(2x^2)*4x$ The answer is the two of these derivatives added together. Does that help?

5. anonymous

thanks alot..

6. anonymous

:)