anonymous
  • anonymous
differentiate 2sin^2x + sin2x^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
correction: sin^2(2x) + sin2x^2
anonymous
  • anonymous
so you're saying \[\sin^2(2x)+\sin(2*x^2)\] or is it \[\sin^2(2x)+\sin((2x)^2)\] ?
anonymous
  • anonymous
the first one

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anonymous
  • anonymous
ok then you can also write it like: \[(\sin(2x))^2+\sin(2x^2)\] and use the chain rule for differentiation in both terms: The derivative of the first term is \[2(\sin(2x))^1*\cos(2x)*2\] The derivative of the second term is \[\cos(2x^2)*4x\] The answer is the two of these derivatives added together. Does that help?
anonymous
  • anonymous
thanks alot..
anonymous
  • anonymous
:)

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