differentiate 2sin^2x + sin2x^2

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

differentiate 2sin^2x + sin2x^2

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

correction: sin^2(2x) + sin2x^2
so you're saying \[\sin^2(2x)+\sin(2*x^2)\] or is it \[\sin^2(2x)+\sin((2x)^2)\] ?
the first one

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

ok then you can also write it like: \[(\sin(2x))^2+\sin(2x^2)\] and use the chain rule for differentiation in both terms: The derivative of the first term is \[2(\sin(2x))^1*\cos(2x)*2\] The derivative of the second term is \[\cos(2x^2)*4x\] The answer is the two of these derivatives added together. Does that help?
thanks alot..
:)

Not the answer you are looking for?

Search for more explanations.

Ask your own question