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anonymous

  • 5 years ago

differentiate 2sin^2x + sin2x^2

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  1. anonymous
    • 5 years ago
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    correction: sin^2(2x) + sin2x^2

  2. anonymous
    • 5 years ago
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    so you're saying \[\sin^2(2x)+\sin(2*x^2)\] or is it \[\sin^2(2x)+\sin((2x)^2)\] ?

  3. anonymous
    • 5 years ago
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    the first one

  4. anonymous
    • 5 years ago
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    ok then you can also write it like: \[(\sin(2x))^2+\sin(2x^2)\] and use the chain rule for differentiation in both terms: The derivative of the first term is \[2(\sin(2x))^1*\cos(2x)*2\] The derivative of the second term is \[\cos(2x^2)*4x\] The answer is the two of these derivatives added together. Does that help?

  5. anonymous
    • 5 years ago
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    thanks alot..

  6. anonymous
    • 5 years ago
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    :)

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