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anonymous
 5 years ago
if segment OU=1. Prove that Tan(alpha)=Sin(alpha)/Cos(alpha).
anonymous
 5 years ago
if segment OU=1. Prove that Tan(alpha)=Sin(alpha)/Cos(alpha).

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Any idea how to do that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use definitions of sin, cos, and tan sin = opposite/hypotenuse cos =adjacent/hypotenuse tan = opposite/adjacent substitute the appropriate lengths and you will see that tan = sin/cos

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but what is the meaning of tan(alpha) and sen(alpha) in the graph. That confuses me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think it comes from unit circle. if OA=1 then the vertical line AA'=sin(alpha) and OA'=cos(alpha)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In the lower side of the triangle I also have a cos(alph).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We dont know OA. We know that OU is 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because AA' = sin(alpha) then we can assume OA=1because sin = opp/hypotenuse = AA'/OA = AA' >therefore OA=1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0clear. Going to try now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im not sure is what I did is righ. Please check it out for me: Tan(alpha)=TU/OU (1) if sin(alpha)=TU/OT, then TU=OTSen(alpha) (2) cos(alpha)=OU/OT, then OU=OTCos(alpha) (3) replacing TU and OU in equation 1, I got Tan(alpha)=Sen(alpha)/Cos(alpha) Is that correcto?
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