anonymous
  • anonymous
if segment OU=1. Prove that Tan(alpha)=Sin(alpha)/Cos(alpha).
Mathematics
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anonymous
  • anonymous
if segment OU=1. Prove that Tan(alpha)=Sin(alpha)/Cos(alpha).
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
The plot is attached
anonymous
  • anonymous
Any idea how to do that?

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dumbcow
  • dumbcow
use definitions of sin, cos, and tan sin = opposite/hypotenuse cos =adjacent/hypotenuse tan = opposite/adjacent substitute the appropriate lengths and you will see that tan = sin/cos
anonymous
  • anonymous
but what is the meaning of tan(alpha) and sen(alpha) in the graph. That confuses me
dumbcow
  • dumbcow
i think it comes from unit circle. if OA=1 then the vertical line AA'=sin(alpha) and OA'=cos(alpha)
anonymous
  • anonymous
In the lower side of the triangle I also have a cos(alph).
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anonymous
  • anonymous
We dont know OA. We know that OU is 1
dumbcow
  • dumbcow
because AA' = sin(alpha) then we can assume OA=1because sin = opp/hypotenuse = AA'/OA = AA' -->therefore OA=1
anonymous
  • anonymous
clear. Going to try now
dumbcow
  • dumbcow
:)
anonymous
  • anonymous
Im not sure is what I did is righ. Please check it out for me: Tan(alpha)=TU/OU (1) if sin(alpha)=TU/OT, then TU=OTSen(alpha) (2) cos(alpha)=OU/OT, then OU=OTCos(alpha) (3) replacing TU and OU in equation 1, I got Tan(alpha)=Sen(alpha)/Cos(alpha) Is that correcto?
dumbcow
  • dumbcow
yes very good

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