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anonymous
 5 years ago
I have to prove that tan(alpha)=sen(alpha)/Cos(alpha) for the following figure ...
anonymous
 5 years ago
I have to prove that tan(alpha)=sen(alpha)/Cos(alpha) for the following figure ...

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im not sure is what I did is righ. Please check it out for me: Tan(alpha)=TU/OU (1) if sin(alpha)=TU/OT, then TU=OTSen(alpha) (2) cos(alpha)=OU/OT, then OU=OTCos(alpha) (3) replacing TU and OU in equation 1, I got Tan(alpha)=Sen(alpha)/Cos(alpha) Is that correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0with sen do you mean sin? and the thing you wrote is a trigonomerty identy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea, so tan(theta)=sin(theta)/cos (theta) wehen i say (theta) that is just an unknown number could be x or anything :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats an identiy so what are you trying to work out?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in the graph I attached you can se that the angle is alpha. However, we can call it theta. The point of this all is to prove the above statement

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry, id love to help but i dont understand your graph :S

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It ok my friend :) by the way. Can you help me with analithic geometry? how to determine the center of a circumference?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry for the typos, but my native language is spanish, no english

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can give it a try but i can garantee that ur gonna get and answer :S
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