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anonymous

  • 5 years ago

I have to prove that tan(alpha)=sen(alpha)/Cos(alpha) for the following figure ...

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  1. anonymous
    • 5 years ago
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  2. anonymous
    • 5 years ago
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    Im not sure is what I did is righ. Please check it out for me: Tan(alpha)=TU/OU (1) if sin(alpha)=TU/OT, then TU=OTSen(alpha) (2) cos(alpha)=OU/OT, then OU=OTCos(alpha) (3) replacing TU and OU in equation 1, I got Tan(alpha)=Sen(alpha)/Cos(alpha) Is that correct?

  3. anonymous
    • 5 years ago
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    with sen do you mean sin? and the thing you wrote is a trigonomerty identy

  4. anonymous
    • 5 years ago
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    yeah sorry Sen=Sin

  5. anonymous
    • 5 years ago
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    yea, so tan(theta)=sin(theta)/cos (theta) wehen i say (theta) that is just an unknown number could be x or anything :)

  6. anonymous
    • 5 years ago
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    thats an identiy so what are you trying to work out?

  7. anonymous
    • 5 years ago
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    in the graph I attached you can se that the angle is alpha. However, we can call it theta. The point of this all is to prove the above statement

  8. anonymous
    • 5 years ago
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    sorry, id love to help but i dont understand your graph :S

  9. anonymous
    • 5 years ago
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    It ok my friend :) by the way. Can you help me with analithic geometry? how to determine the center of a circumference?

  10. anonymous
    • 5 years ago
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    sorry for the typos, but my native language is spanish, no english

  11. anonymous
    • 5 years ago
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    i can give it a try but i can garantee that ur gonna get and answer :S

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spraguer (Moderator)
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