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anonymous

  • 5 years ago

now if y=mx+b^2 how do i find the ancwer

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  1. anonymous
    • 5 years ago
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    What's the question?

  2. anonymous
    • 5 years ago
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    y=mx+b^2 y=m thats it

  3. anonymous
    • 5 years ago
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    sorry but we dont understand that

  4. amistre64
    • 5 years ago
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    b is a constant; so it doesnt matter what degree it is

  5. anonymous
    • 5 years ago
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    You have two lines, are we to figure out their intersection? What are we solving?

  6. amistre64
    • 5 years ago
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    its 16...no it isnt it 4^2... no it isnt its sqrt(256)...no it isnt it 9+7.....

  7. anonymous
    • 5 years ago
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    thats all my book says its says i dont understand it its so confusing sove these problems with a graph y=mx+b^2 y=b

  8. anonymous
    • 5 years ago
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    ugh i give up.

  9. anonymous
    • 5 years ago
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    Don't give up, that second statement that you typed, y=b. The first time it was y=m which one is it?

  10. anonymous
    • 5 years ago
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    sorry i ment y=m y=m

  11. anonymous
    • 5 years ago
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    So it says to solve by graphing, y=m (assuming m is just a number and not the slope) is just a horizontal line...as for the y=mx+b^2 I don't know how to graph that without points to help me find the b (y-intercept)

  12. anonymous
    • 5 years ago
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    if y=m and m is the slope then you have a line that starts at (0,0) and has a positive slope of 1

  13. anonymous
    • 5 years ago
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    but then it should say y=mx

  14. anonymous
    • 5 years ago
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    or y=x sorry...

  15. anonymous
    • 5 years ago
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    wait...THATS IT! IT DOSE START AT 0,0 THANKS SOOO MUCH!!!!!!!

  16. anonymous
    • 5 years ago
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    bye

  17. anonymous
    • 5 years ago
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    bye :)

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