anonymous
  • anonymous
now if y=mx+b^2 how do i find the ancwer
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
What's the question?
anonymous
  • anonymous
y=mx+b^2 y=m thats it
anonymous
  • anonymous
sorry but we dont understand that

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amistre64
  • amistre64
b is a constant; so it doesnt matter what degree it is
anonymous
  • anonymous
You have two lines, are we to figure out their intersection? What are we solving?
amistre64
  • amistre64
its 16...no it isnt it 4^2... no it isnt its sqrt(256)...no it isnt it 9+7.....
anonymous
  • anonymous
thats all my book says its says i dont understand it its so confusing sove these problems with a graph y=mx+b^2 y=b
anonymous
  • anonymous
ugh i give up.
anonymous
  • anonymous
Don't give up, that second statement that you typed, y=b. The first time it was y=m which one is it?
anonymous
  • anonymous
sorry i ment y=m y=m
anonymous
  • anonymous
So it says to solve by graphing, y=m (assuming m is just a number and not the slope) is just a horizontal line...as for the y=mx+b^2 I don't know how to graph that without points to help me find the b (y-intercept)
anonymous
  • anonymous
if y=m and m is the slope then you have a line that starts at (0,0) and has a positive slope of 1
anonymous
  • anonymous
but then it should say y=mx
anonymous
  • anonymous
or y=x sorry...
anonymous
  • anonymous
wait...THATS IT! IT DOSE START AT 0,0 THANKS SOOO MUCH!!!!!!!
anonymous
  • anonymous
bye
anonymous
  • anonymous
bye :)

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