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anonymous
 5 years ago
now if y=mx+b^2 how do i find the ancwer
anonymous
 5 years ago
now if y=mx+b^2 how do i find the ancwer

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y=mx+b^2 y=m thats it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry but we dont understand that

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0b is a constant; so it doesnt matter what degree it is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have two lines, are we to figure out their intersection? What are we solving?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0its 16...no it isnt it 4^2... no it isnt its sqrt(256)...no it isnt it 9+7.....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats all my book says its says i dont understand it its so confusing sove these problems with a graph y=mx+b^2 y=b

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Don't give up, that second statement that you typed, y=b. The first time it was y=m which one is it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So it says to solve by graphing, y=m (assuming m is just a number and not the slope) is just a horizontal line...as for the y=mx+b^2 I don't know how to graph that without points to help me find the b (yintercept)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if y=m and m is the slope then you have a line that starts at (0,0) and has a positive slope of 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but then it should say y=mx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait...THATS IT! IT DOSE START AT 0,0 THANKS SOOO MUCH!!!!!!!
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