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anonymous
 5 years ago
if x+1/x =8, find the x^2 + x^2
anonymous
 5 years ago
if x+1/x =8, find the x^2 + x^2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is it \[{x+1 \over x}=8?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x + 1/x)^2 = x^2 + 2 + 1/x^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It is further = x^2 + 2 + x^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0finally (x + 1/x)^2  2 = x^2 + x^2 a

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x+{1 \over x}=8 \implies x^2+2+x^{2}=16 \implies x^2+x^{2}=14\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You hv x + 1/x = 8 Squaring both sides (x + 1/x)^2 = 8^2 = 16 S0, 16  2 = x^2 + x^2 so 14 is the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry not 16, it's 64. So the final answer is 62.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer I have are: a) 60, b)58, c)62, d)0, e)non So the answer must be e)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[x+{1 \over x}=8 \implies (x+{1 \over x})^2=8^2 \implies x^2+2+x^{2}=64 \] \[\implies x^2+x^{2}=62\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Here is the corrected version You hv x + 1/x = 8 Squaring both sides (x + 1/x)^2 = 8^2 = 64 S0, 64  2 = x^2 + x^2 so 62 is the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You got the idea emunrradtvamg?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, thanks guys its clear now
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