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what are you supposed to do about it?

solve it

it is not an equation. you cant solve it.

cant it be simplified?

You want to simplify it?

yes

Is it log (2x), or log x to base 2?

it is log((2x/y)^2)-log 75

log 2x

not that log a - log b = log(a/b) and log a +log b = log(ab)

how did u get the answer dhatraditya?

note*

note also that xlog a = log a^x

I think this is the simplest it can be.

so its simplified form is log ((2x/y)^2/75))

What AnwarA has.

thank you so much

You're welcome!

how did u get the 75?

3*5^2=3(25)=75

i understand now.thx

you are welcome.

solve log base x (5x+24)=2

x = 8 or -3

since logs are not defined for negative numbers, x = 8

do you know how I arrived at the answer, leona?

?how did u work it out

do you know how logarithms work?

i know some of the rules

tell me what you know about logs? what do you understand by logs?

i know that the logarithm of 1 regardless of the base is one

if i told you log 32 to the base 4 is 2.5, what do I mean by that?

that 4 ^2.5 is 32

exactly! good!
have you tried that in your calculator?

yes

so you understand that any number can be represented as a power of another number?

yes

okay good. so what do i mean when i say log(5x+24) to the base x is 2?

it means that x raise to the power 2 equal (5x+24)

I should have said any POSITIVE number can be represented as apower of any other number (the base)

right,
so x^2 = 5x+24

this is a simple quadratic equation

should i square the x^2?

why would you want to do that?

i dont know how to remove the x

okay have you solved quadratic equations before?

yes

can you see that x^2 = 5x+24 can be rearranged so that it is in the form
ax^2+bx+c = 0?

ohh yea

what r the two factors? cant find them

post your equation.

x^2-5x-24=0

i got 8

yeah!!!!!!

did you use the quadratic formula or the factoring method?

quadratic

i did

okay, do you know the reason why you discarded -3?

because log not defined for negative numbers

no, its because logs with negative bases only work for even powers.
anyway, good job! have a medal.

ok thank you

you are welcome.

ill do that

:)

are u going to be online in the night?

i dont know. I generally come here in my free time to help out.

ohh cause i ave exam 2marow and i need more help with other topics

ok am going to try this question log base x (5x+14)=2

okay, lemme know how it works out. you should get 7

i got 7....using the factoring method

okay good.

thank you

your latest logarithm question will go like : \[5x +14=x^{2}\]

so \[x ^{2}-5x-14=0 and then you solve with the quadratic formula \]

need help with this 1....log base 4 (1) +log (25)

okay, what does log base 4 (1) mean?

log to base 4 to a number = 1

like 4\[4^{x}=1 \]

that means x=0

because

\[4^{0}\]

ohh yeah thats a rule of logs

so 5^2=25

right, log 25 = log 5^2 = ?

yeah so the final answer is log 5^2=25

log 25 without a base specified means the base is a standard base of ten (10)

so are you saying that 10^25 = 5^2, leona?

so it shd read like \[\log_{10} 25=x\]

which means 25=\[10^{x}\]

no am nt

then what do yoou mean by log 5^2 = 25?

sinse it doent ave a base its base 10 rite?

so x=\[x= \log 25/\log 10\]

yes, we assume that the base is 10 if it is not specified

yas since it doesnt have any base it means base ten
...youre rite

so i should use the rule of change of base

log 25 is simply log 5^2 = 2log5

are you required to find the numerical value of log 25?

if you are, just punch it in your calculator and you have your answer.

no that was nt required

then it is simply log 25, which can be written as 2 log 5

ok..

since we know that x log a = log a^x

ok i now understand that rule

2logx-log(2+3x)=1

okay, use the identities. x log a = log a^x
and log a - log b = log(a/b)

ok

take it one step at a time.
what is 2 log x = ?

log x^2

okay and what is log x^2-log(2+3x)?

would it be base 10 since no base is given?

yes

10^1

is zero

no, i meant log a - log b is log(a/b)
so log (x^2) = log (2+3x) = ?

sorry log (x^2) - log (2+3x) = ?

am stuck

okay it is log(x^2/(2+3x)

so log (x^2/(2+3x)) = 1

yes

so if log A to the base 10 is 1, what do i mean by that?

10^1=a

yes, so if i say log(x^2/(2+3x)) = 1, what do i mean by that?

it means log 1 = x^2/2+3x

no, pay attention to the last two statements i made and post your answer. think about it carefully.

i still dont get it

if log a = 1 means a = 10^1
then log(x^2/(2+3x)) =1 means x^2/2+3x = 10^1

ohhhhhhhh...:)

now its just a quadratic equation. solve it and find the values of x

rearrange it for me plz

no, you can do this on your own. multiply both sides by 2+3x and post what you got.

4+12x+9x^2=20 +30x

\[x ^{2}/(2+3x) = 10\]

multiply both sides by (2+3x) to get
\[x ^{2} = 30x+20\]

yea i ave that down

I dont understand how you got 4+12x+9x^2=20 +30x

do you know how to manipulate equations?

no

i get it now

http://www.chem.tamu.edu/class/fyp/mathrev/mr-algeb.html

ok