anonymous
  • anonymous
please help me, i got final exam tomorrow integrate : [(2+arctan 3x)^(1/2) / 1+9x^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Let\[3x =\theta\]
amistre64
  • amistre64
let 3x=theta?
amistre64
  • amistre64
the bottom is the derivative of the top :)

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amistre64
  • amistre64
well, the top innnards
anonymous
  • anonymous
May be you have an easier way.
amistre64
  • amistre64
trig sub it lol.. no really u = 2+tan^-1(3x) du = 3/(1+9x^2) dx dx = (1+9x^2)/3
amistre64
  • amistre64
(1+9x^2) u^(1/2) --------------- (1+9x^2) 3 (1/3) [S] u^(1/2) du
anonymous
  • anonymous
Good, my way was much more labor.
amistre64
  • amistre64
lol.... i like laborious :)

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