anonymous
  • anonymous
Can someone solve this please? the points (2,6) and (3,18) lie on the curve y=ax^n use logarithms to find the values of a and n, giving your answers correct to 2d.p. thanks :)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
6 = a(2^n) ------> a = 6/2^n 18 = a(3^n)-------> 18 = 6(3^n)/(2^n)---->3 = 3^n/2^n
anonymous
  • anonymous
3 = (3/2)^n
anonymous
  • anonymous
i dont know what you did :(

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anonymous
  • anonymous
how did you get 3=(3/2)^n?
anonymous
  • anonymous
because 18 = 6(3/2)^n, divide both sides by 6
anonymous
  • anonymous
ok :)
anonymous
  • anonymous
but i need a number with 2dp :S
anonymous
  • anonymous
okay. so we have 3 = (3/2)^n take log on both sides log 3 = log(3/2)^n -------> log 3 = n log(3/2) ----> n = log 3/ log(3/2) use calculator to find the value of n to 2 dp
anonymous
  • anonymous
2.71!!! YAYA! thanks ill give u a medal :)
anonymous
  • anonymous
you are welcome.
anonymous
  • anonymous
use n to find a by substituting in one of the equations.
anonymous
  • anonymous
oh :( i thought that the qs ended ill do that now then :)
myininaya
  • myininaya
ok I got n=log(1/3) /log(2/3) maybe I made a mistake
anonymous
  • anonymous
:S
myininaya
  • myininaya
oh wait it might be the same thing lol
anonymous
  • anonymous
ya lol
myininaya
  • myininaya
there are so many properties with log
myininaya
  • myininaya
the reason they are the same is : log(1/3) /log(2/3)=[log1-log3]/[log2-log3]=[0-log3]/[(-1)(log3-log2)]=log3/[log3/2]
anonymous
  • anonymous
wow, it looks like a sentence without any words XD
anonymous
  • anonymous
its not hard to understand if you think about it, Miss.
anonymous
  • anonymous
n=ln3\(ln3/2) et a=6/[2^(ln3/2)]
anonymous
  • anonymous
i dont actually understand it it looks like random equations put together :p
anonymous
  • anonymous
okay. I hope for your sake that you are not taking math as a major course then :)
anonymous
  • anonymous
no, really wanna drop it next year. its way too hard i cant manage it :(
anonymous
  • anonymous
yes, some people are good at certain things, others are good at other things.

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