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6 = a(2^n) ------> a = 6/2^n 18 = a(3^n)-------> 18 = 6(3^n)/(2^n)---->3 = 3^n/2^n
3 = (3/2)^n
i dont know what you did :(
how did you get 3=(3/2)^n?
because 18 = 6(3/2)^n, divide both sides by 6
but i need a number with 2dp :S
okay. so we have 3 = (3/2)^n take log on both sides log 3 = log(3/2)^n -------> log 3 = n log(3/2) ----> n = log 3/ log(3/2) use calculator to find the value of n to 2 dp
2.71!!! YAYA! thanks ill give u a medal :)
you are welcome.
use n to find a by substituting in one of the equations.
oh :( i thought that the qs ended ill do that now then :)
ok I got n=log(1/3) /log(2/3) maybe I made a mistake
oh wait it might be the same thing lol
there are so many properties with log
the reason they are the same is : log(1/3) /log(2/3)=[log1-log3]/[log2-log3]=[0-log3]/[(-1)(log3-log2)]=log3/[log3/2]
wow, it looks like a sentence without any words XD
its not hard to understand if you think about it, Miss.
n=ln3\(ln3/2) et a=6/[2^(ln3/2)]
i dont actually understand it it looks like random equations put together :p
okay. I hope for your sake that you are not taking math as a major course then :)
no, really wanna drop it next year. its way too hard i cant manage it :(
yes, some people are good at certain things, others are good at other things.