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anonymous
 5 years ago
Help me please...
your given that: u(base 1)=1 and u(base n+1)=u(base n)/1+u(base n)
Find the values of U (base 2), U(base 3) and U (base 4). give your answers as a fraction
and please be so nice to explain it
anonymous
 5 years ago
Help me please... your given that: u(base 1)=1 and u(base n+1)=u(base n)/1+u(base n) Find the values of U (base 2), U(base 3) and U (base 4). give your answers as a fraction and please be so nice to explain it

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1that looks like recursion formulas

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[U_{n+1} = \frac{U_{n}}{1+U_{n}}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1U{1} = 1 so.... U{2} = 1/(1+1) = 1/2 U{3} = (1/2)/(1+(1/2)) = 1/3 U{4} = [1/3]/ [1+(1/3)] = 1/4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1you just keep reiterating the past amount to find the present amount

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1'btm' works with themand his material calls them difference equations..... which seems an archaic term

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you very much medal earned :)
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