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anonymous

  • 5 years ago

Help me please... your given that: u(base 1)=1 and u(base n+1)=u(base n)/1+u(base n) Find the values of U (base 2), U(base 3) and U (base 4). give your answers as a fraction and please be so nice to explain it

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  1. amistre64
    • 5 years ago
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    that looks like recursion formulas

  2. amistre64
    • 5 years ago
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    \[U_{n+1} = \frac{U_{n}}{1+U_{n}}\]

  3. amistre64
    • 5 years ago
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    U{1} = 1 so.... U{2} = 1/(1+1) = 1/2 U{3} = (1/2)/(1+(1/2)) = 1/3 U{4} = [1/3]/ [1+(1/3)] = 1/4

  4. amistre64
    • 5 years ago
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    you just keep reiterating the past amount to find the present amount

  5. amistre64
    • 5 years ago
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    'btm' works with themand his material calls them difference equations..... which seems an archaic term

  6. anonymous
    • 5 years ago
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    thank you very much medal earned :)

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