anonymous
  • anonymous
Find the vector v, and its magnitude is 5. v is orthogonal to x axis, and the dot product v.w = 6, and the vector w=i+2j.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
v.w=|v||w|cos theta
amistre64
  • amistre64
a vetor that is perpendicular to the x axis with a magnitude of 5 is <0,5>
amistre64
  • amistre64
is this vector in R^3?

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myininaya
  • myininaya
does v have ai+bj form or does v have ai+bj+ck form?
myininaya
  • myininaya
2 dimensions or 3?
amistre64
  • amistre64
if w=<1,2>....... v.w = (1.0)+(5.2) = 10...not 6
amistre64
  • amistre64
the question makes no sense...
amistre64
  • amistre64
(1.0)+(2.3) = 6 but then v =<0,3> with a magnitude of 3
anonymous
  • anonymous
the answer is <0,3,4>
amistre64
  • amistre64
the answer is...... clarify the question lol
myininaya
  • myininaya
i got what amistre got
myininaya
  • myininaya
a condradiction
amistre64
  • amistre64
find the real roots of x^2 +9
anonymous
  • anonymous
but i dont understand how he got the number 4 in the answer
amistre64
  • amistre64
oh..by the way; when i say real rots i mean complex lol
myininaya
  • myininaya
ok so we are looking at 3 dimensions not 2
amistre64
  • amistre64
<1,2,0> <0,3,4> -------- 6...yes
amistre64
  • amistre64
so....<0,3> is what it looks like when staring at it from the xy plane
amistre64
  • amistre64
0^2 +3^2 +z^2 = |v|^2
amistre64
  • amistre64
9+z^2 = 5^2 z^2 = 25 - 6 z = sqrt(16) = 4
amistre64
  • amistre64
-6 means -9 :)
myininaya
  • myininaya
thats what I did :)
amistre64
  • amistre64
lol..its like haveing a parrot :)
anonymous
  • anonymous
hey, may you type in the word and send me?
amistre64
  • amistre64
just copy it off of here and put it in a text editor.. like SWord or notepad
amistre64
  • amistre64
....my shift keys are on the fritz...
myininaya
  • myininaya
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anonymous
  • anonymous
Thanks a lot

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