Find the vector v, and its magnitude is 5. v is orthogonal to x axis, and the dot product v.w = 6, and the vector w=i+2j.

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Find the vector v, and its magnitude is 5. v is orthogonal to x axis, and the dot product v.w = 6, and the vector w=i+2j.

Mathematics
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v.w=|v||w|cos theta
a vetor that is perpendicular to the x axis with a magnitude of 5 is <0,5>
is this vector in R^3?

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Other answers:

does v have ai+bj form or does v have ai+bj+ck form?
2 dimensions or 3?
if w=<1,2>....... v.w = (1.0)+(5.2) = 10...not 6
the question makes no sense...
(1.0)+(2.3) = 6 but then v =<0,3> with a magnitude of 3
the answer is <0,3,4>
the answer is...... clarify the question lol
i got what amistre got
a condradiction
find the real roots of x^2 +9
but i dont understand how he got the number 4 in the answer
oh..by the way; when i say real rots i mean complex lol
ok so we are looking at 3 dimensions not 2
<1,2,0> <0,3,4> -------- 6...yes
so....<0,3> is what it looks like when staring at it from the xy plane
0^2 +3^2 +z^2 = |v|^2
9+z^2 = 5^2 z^2 = 25 - 6 z = sqrt(16) = 4
-6 means -9 :)
thats what I did :)
lol..its like haveing a parrot :)
hey, may you type in the word and send me?
just copy it off of here and put it in a text editor.. like SWord or notepad
....my shift keys are on the fritz...
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Thanks a lot

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