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well; angleC = 180-40-41
since only one side is given; use the law of sines to get another sides
a 60 c ----- = ----- = ----- sin(41) sin(40) sin(C)
99 sounds good :)
ugh...this is hard!
nah; just tedious :)
you must come here offten ; ) hehe u answer all my questions.
...its true, this websites is my guilty pleasure lol
well good because im awefull at math and need YOUR help.
what are you good at?
during lunch period i would sit out in the courtyard and beat up people playing chess..... i mean beat people at chess :)
bahahaha sounds very exciting. how old are u?
old enough to know how to play chess lol....
and that would beee?
im not trying to pick u up lol i just need to make sure my homework is in good - experienced hands
i remember when..... brass was considered new
so ur like 87
close to it lol
closer to it everyday
alrigghhtttyyy, next problem.
dod you get the answers to this problem?
a = 99(sin41)/sin(40)
.....not 99....what whas b?
b is 60.
a = 60sin(41)/sin(40)
c = 60sin(99)/sin(40)
a is about 60.... since it is close to 60*1
c is abt 92.19
those are side lengths ya know
when it says to solve the triangle is that wanting all the lengths added together?
no; to solve a triangle means to find the measurements of all 6 parts; 3 angles and 3 sides
it gave you 3 of those parts; find the other 3
C = 99 a = 60.001...... b = 92.19......
lol....c = 92.19....
lol ill need your help later too! im in theatre now so im getting off here