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anonymous
 5 years ago
Simplify completely:
6x^2+5x+1

27x^3+1
anonymous
 5 years ago
Simplify completely: 6x^2+5x+1  27x^3+1

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know the 27x^3+1 is a perfect cube: cuberoot 27= 3 cuberoot x^3=x cuberoot 1=1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but the top can't be factored. I think I can rewrite this as (3x+1)^3 But would that make the answer 6x^2+5x+1  ? (3x+1)^3 I can't help but think there is more to this.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0factorize the denominator..an equation in the form a^3 + b^3 = (a+b)(a^2ab+b^2) also factorize the numerator. the numerator can be factorized by using the formula x = \[b \pm \sqrt{D} \div 2a\] where the quadratic is in the form ax^2 + bx + c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so (3x+1)(9x^23x+1^2)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah thats the denominator.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Or: \[(3x+1)(9x^23x+1)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So the numerator just stays the same then?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no. factorize the numerator using the formula i gave you..the formula gives you the roots of the equation. if a is the 1st root and b is the 2nd root then the numerator can be re written as (xa)(xb)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It won't work that way because there are 2 + signs, which means the signs must stay the same. Nothing but 1*1 will = +1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it will. D = 1. 25 (6*4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(6x1)(x1) = 6x^26x1x+1 = 6x^27x+1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That doesn't match the equation. Where did you get a 4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the formula i gave you is b^2  4ac. hence the 4..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But you can't use negatives when both signs in the equation are positive.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[6x^2+5x+1\] That means you have to use + signs to factor from what I have been told.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nope..for any quadratic expression of the form \[Ax ^{2} + Bx + C\] the formula for the roots are \[B \pm \sqrt{D} / 2A \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What is D then? The entire equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no..i told you D is the discriminant of the equation which is equal to B^2  4AC

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So \[5 \pm \sqrt{5^24(6)(1)} \div 2(6)\] ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[5 \pm \sqrt{2524} \div 12\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.06  12 or 4  12

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But they are fractions. How am I supposed to plug those into the equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the equation can be written as (x+1/3)(x+1/2) = 0.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, I typed them wrong, I see that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But how does it help if it equals 0? That would solve for x for the top equation, but I am simplifying.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I thought the quadratic formula was for determining the values of x?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry it doesnt equal 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its just that the numerator can be re written as (x+1/3)(x+1/2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And also, (x+1/3_)x+1/2) \[\neq\] to \[6x^2+5x+1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry, *(x+1/3)(x+1/2) \[\neq 6x^2+5x+1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thats why I was saying it can't be factored.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is equal to that divided by 6. you can always multiply and divide 6 and retain the eqn.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But it is already in a fraction. I can't have a fraction over a fraction and call it simplified.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay, figured something out, but didn't need quadratic formula for it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{(1+2 x)}{(1+6 x)^2} \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry. The denominator should be: \[\left(13 x+9 x^2\right) \] \[\frac{6 x^2+5 x+1}{27 x^3+1}=\frac{1+2 x}{13 x+9 x^2} \]
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