anonymous
  • anonymous
can anyone explain how to do parabola's in great detail
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
yeah..fire away
anonymous
  • anonymous
wat d u want to know exactly?
anonymous
  • anonymous
study all the four standard forms and the general forms of parabolae carefully...learn how to evaluate the vertex, latusrectum and directrix and focus and centre

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anonymous
  • anonymous
how to figure out the vertex directrix and focus if they only give me a lil information
anonymous
  • anonymous
giv me d info
anonymous
  • anonymous
vertex (-2,0) directrix y=-4 and i have 2 find the equation and graph it
anonymous
  • anonymous
(x+2)^2= 16y
anonymous
  • anonymous
ok now can u teach me how to get that
anonymous
  • anonymous
sure
anonymous
  • anonymous
u c if u have d directrix parallel to x-axis, its a vertical parabola upward or dwnward
anonymous
  • anonymous
since here d vertex lies above d directrix its an upward parabola
anonymous
  • anonymous
ok so do i use (x-h)^2=4p(y-k)
anonymous
  • anonymous
yeah bingo...where p is the distance btween d vertex and directrix
anonymous
  • anonymous
got it?
anonymous
  • anonymous
no i just know the formula 2 use but idk how 2 use it
anonymous
  • anonymous
well now u kno
anonymous
  • anonymous
no i dont how did u get the answer wat are the steps wat did u plug in
anonymous
  • anonymous
u kno d formula...jst remmbr u use dis only when the directrix is parallel to x-axis
anonymous
  • anonymous
when d directrix is y=something, u use it
anonymous
  • anonymous
ok but wat steps did u take to get the answer i knoow 2 use the fromula but idk how 2 get the answer
anonymous
  • anonymous
see h and k are the x and y co-ordinates of the vertex. and p is the distance of the vertex from directrix
anonymous
  • anonymous
so far all i have is (x-2)^2=4py
anonymous
  • anonymous
so p=3???
anonymous
  • anonymous
p is 4 the distance of -2,0 from y=-4
anonymous
  • anonymous
so p=-4
anonymous
  • anonymous
4 distance is always positive
anonymous
  • anonymous
ok
anonymous
  • anonymous
so uve got (x+2)^2 = 4.4(y)
anonymous
  • anonymous
thanks do you mind helping me wit some more
anonymous
  • anonymous
no i dont..
anonymous
  • anonymous
(x+2)^2=16y
anonymous
  • anonymous
wat i got
anonymous
  • anonymous
thats ryt i spose
anonymous
  • anonymous
focus (0,0) directrix x=4
anonymous
  • anonymous
hold on on dat last one was my parabola suppose 2be upward and my directrix was suppose 2 go through it right???
anonymous
  • anonymous
no ur getting muddled up..the directrix doesnt go thru d parabola
anonymous
  • anonymous
well when i graphed it it did cuz the y axis is vertical and not horizontial so is my parabola not facing the right way
anonymous
  • anonymous
no ur parabola shld touch the x-axis, pass thru -2,0 and the directrix should be 4 units below it
anonymous
  • anonymous
ok i had it right the 1st time so on to the next one lol
anonymous
  • anonymous
ws i wrong?
anonymous
  • anonymous
idk lol idc 4real im sick of dis class
anonymous
  • anonymous
ready 2 help me wit the other 1
anonymous
  • anonymous
yeah
anonymous
  • anonymous
focus (0,0) directrix x=4
anonymous
  • anonymous
wat way will the directrix be going
anonymous
  • anonymous
vertical
anonymous
  • anonymous
ok
anonymous
  • anonymous
now 2 figure out the equation do i use (y-k)^2=4p(x-h)
anonymous
  • anonymous
and is this going 2 be opening to the left
anonymous
  • anonymous
ur right...u do it quite well..yr u sick of it?
anonymous
  • anonymous
y^2=-16x
anonymous
  • anonymous
cuz idk how 2 do it im just guessing
anonymous
  • anonymous
no bt ur guessin right so u shld get confidence
anonymous
  • anonymous
so wat is the vertex and if i dont have (h,k) do i use x,y
anonymous
  • anonymous
use 0,0 for h,k..so its y^2=-16x
anonymous
  • anonymous
ok so anytime i dont have the vertex use 0,0
anonymous
  • anonymous
bt ur vertex is given 0,0
anonymous
  • anonymous
dat was the focus
anonymous
  • anonymous
OH IMSORRY
anonymous
  • anonymous
rly sorry..bt u cn frgv a lovesick man cant u...
anonymous
  • anonymous
lol sure so how do i do it
anonymous
  • anonymous
neway so the vertex is the midpt of the focus and the pt where d directrix meets the axis
anonymous
  • anonymous
i need numbers to do the formula
anonymous
  • anonymous
so its d midpt of 0,0 and 4,0
anonymous
  • anonymous
so the vertex is 2,0
anonymous
  • anonymous
oooooo ok but y lol
anonymous
  • anonymous
ur having fun arent u...d midpt of 0,0 and 4,0 is (0+4)/2, 0+0/2
anonymous
  • anonymous
vertex is d midpt of the focus and the directrix meeting the axis
anonymous
  • anonymous
u should be my teacher u making it simple my teacher is making it hard ok so i can always use dat when i am givin the focus and directrix right
anonymous
  • anonymous
is the answer y^2=-8px
anonymous
  • anonymous
thnx fr d compliment..wt grade r u in?
anonymous
  • anonymous
11th
anonymous
  • anonymous
im in ap math
anonymous
  • anonymous
nahi...replace d x with (x-2)
anonymous
  • anonymous
cz d vertex is 2,0
anonymous
  • anonymous
so y^2=4p(x-2)
anonymous
  • anonymous
yeah
anonymous
  • anonymous
ok dis one i did they gave me the center (-7,3) and the focus (-7,5) i got (x+7)^2=-24y is dat right
anonymous
  • anonymous
(x+7)^2 = 8(y-3)
anonymous
  • anonymous
ok
anonymous
  • anonymous
now the other problems r harder they gave me just a graph wit the drawing already made so i hope i can explain dis 2 u
anonymous
  • anonymous
try
anonymous
  • anonymous
the is (-4,3) and the directrix is (7,2.5)
anonymous
  • anonymous
ur doing somthin wrng
anonymous
  • anonymous
the vertex was the (-4,3)
anonymous
  • anonymous
is it (x-3)^2=4p(y+4)
anonymous
  • anonymous
yeah
anonymous
  • anonymous
ok
anonymous
  • anonymous
ok the vertex is (-2,_6) and they gave me 2.25 wat do i do
anonymous
  • anonymous
(-2,-6)
anonymous
  • anonymous
whts dis 2.25
anonymous
  • anonymous
x=2.25
anonymous
  • anonymous
so its (y+6)^2 = - 17(x+2)
anonymous
  • anonymous
where u get -17
anonymous
  • anonymous
4.25 x 4
anonymous
  • anonymous
where u get 4.25
anonymous
  • anonymous
distance of -2 from 2.25
anonymous
  • anonymous
u lost me now i have (y=6)^2=4p(2.25+2)
anonymous
  • anonymous
(y+6)^2
anonymous
  • anonymous
= 4.25(4) (x+2)
anonymous
  • anonymous
so p=4.25
anonymous
  • anonymous
yeah right
anonymous
  • anonymous
but how u know to do 2.25+2 then to make dat p
anonymous
  • anonymous
remmbr its d distance between d vertex and directrix
anonymous
  • anonymous
now im all lost x=2.25 is the directrix right
anonymous
  • anonymous
yes and x=-2 is the vertex so d distance of it from 2.25 is 4.25
anonymous
  • anonymous
my bad the directrix is x=-2.5
anonymous
  • anonymous
x=-2.25
anonymous
  • anonymous
so its only .25
anonymous
  • anonymous
its from -2 to 2.25 so it 2.25 - (-2) = 4.25
anonymous
  • anonymous
no if vertex is -2 and the directrix is -2.25 there only 1/4 apart
anonymous
  • anonymous
am i wrong
anonymous
  • anonymous
if directrix is 2.25 then yes
anonymous
  • anonymous
no the directrix is negative
anonymous
  • anonymous
so wats the new answer
anonymous
  • anonymous
then ur right
anonymous
  • anonymous
so (y+6)^2=p(x+2)
anonymous
  • anonymous
yeah
anonymous
  • anonymous
yay thank u so much
anonymous
  • anonymous
r u good at doing dis wit word problems
anonymous
  • anonymous
nvm if i get stuck ill post it but thanks 4 all ur help
anonymous
  • anonymous
no prob
anonymous
  • anonymous
can u help me

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