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anonymous

  • 5 years ago

find the x value of the point of the curve y=3x+2 closest to the point (1,0)

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  1. chaise
    • 5 years ago
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    That equation is not a curved line, that equation is a straight line (y=mx+b),

  2. anonymous
    • 5 years ago
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    ok...but this is what it says on my test

  3. anonymous
    • 5 years ago
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    What class?

  4. anonymous
    • 5 years ago
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    calculus I

  5. myininaya
    • 5 years ago
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    distance=d=sqrt((1-x)^2+(0-(3x+2)^2) minimizing distance will give you same minimum if you minimize d^2 d^2=(1-x)^2+(3x+2)^2 (d^2)'=..... you finish this i have to go

  6. anonymous
    • 5 years ago
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    you could find the min value between the point (1,0) and (x,3x+2) using the distance formula and then set the derivative of the distance fomula to 0

  7. anonymous
    • 5 years ago
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    oh ok. Thnks guys

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spraguer (Moderator)
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