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anonymous

  • 5 years ago

Ten cards are numbered from 1 to 10 and placed in a box. One card is selected at random and replaced. Another card is selected at random. What is The probability of selecting a multiple of 3 and then a multiple of 2?

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  1. anonymous
    • 5 years ago
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    How many multiples of 3 are there, and how many multiples of 2?

  2. anonymous
    • 5 years ago
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    the probability of selecting multiples of 3 and multiples of 2

  3. anonymous
    • 5 years ago
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    I'm confused.

  4. anonymous
    • 5 years ago
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    No, I'm saying count how many there are first. 1 2 is a multiple of 2 3 is a multiple of 3 4 is a multiple of 2 5 6 is a multiple of 2 and a multiple of 3 7 8 is a multiple of 2 9 is a multiple of 3 10 So how many multiples of 2 are there in the box? How many multiples of 3?

  5. anonymous
    • 5 years ago
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    4 multiples of 2 and 3 multiples of 3.

  6. anonymous
    • 5 years ago
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    Count again.

  7. anonymous
    • 5 years ago
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    5 multiples of 2 and 3 multiples of 3

  8. anonymous
    • 5 years ago
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    Correct. So when you pick the first card, what is the probability it will be a multiple of 3?

  9. anonymous
    • 5 years ago
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    3

  10. anonymous
    • 5 years ago
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    30%

  11. anonymous
    • 5 years ago
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    Ok, and you put the first card back and pick again. What are the odds of picking a multiple of 2?

  12. anonymous
    • 5 years ago
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    50%

  13. anonymous
    • 5 years ago
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    Correct. So the odds of doing one and the other is: P(A and B) = P(A) * P(B) = .3 * .5 =

  14. anonymous
    • 5 years ago
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    So 15%

  15. anonymous
    • 5 years ago
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    I believe that should be correct yes.

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