Ten cards are numbered from 1 to 10 and placed in a box. One card is selected at random and replaced. Another card is selected at random. What is The probability of selecting a multiple of 3 and then a multiple of 2?
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How many multiples of 3 are there, and how many multiples of 2?
the probability of selecting multiples of 3 and multiples of 2
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No, I'm saying count how many there are first.
2 is a multiple of 2
3 is a multiple of 3
4 is a multiple of 2
6 is a multiple of 2 and a multiple of 3
8 is a multiple of 2
9 is a multiple of 3
So how many multiples of 2 are there in the box?
How many multiples of 3?
4 multiples of 2 and 3 multiples of 3.
5 multiples of 2 and 3 multiples of 3
So when you pick the first card, what is the probability it will be a multiple of 3?
Ok, and you put the first card back and pick again. What are the odds of picking a multiple of 2?
So the odds of doing one and the other is:
P(A and B) = P(A) * P(B) = .3 * .5 =