how can i solve a quadratic equation like this 6x^2-5+x=0

- anonymous

how can i solve a quadratic equation like this 6x^2-5+x=0

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- anonymous

rewrite it in the normal form and plug into the quadratic equation:
\[ax^2 + bx + c = 0 \implies x = \frac{-(b) \pm \sqrt{(b)^2-4(a)(c)}}{2(a)}\]

- anonymous

thank you i did that part but where i am getting cofused at is that addition/ subtraction sign i dont kno what to do with it sorry i didnt say that earlier

- anonymous

Oh, well unless the part under the square root is 0 you will get 2 different possible solutions.
\[x = \frac{-(b) + \sqrt{(b)^2-4(a)(c)}}{2(a)}\]
and
\[x = \frac{-(b) - \sqrt{(b)^2-4(a)(c)}}{2(a)}\]
The \(\pm\) thing just makes it easier to write.

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## More answers

- anonymous

oh ok thank you i'ma try it now :D

- anonymous

HOW WOUD I GET THAT SQUARE ROOT SYMBOL ON THE CALCULATOR

- anonymous

It should have it. If not you can raise it to the .5 power.

- anonymous

LIKE THIS (1^2-4(6)(-5)^5

- anonymous

it gave me some crazy number how would you do it i guess i was wrong

- anonymous

i got 2.59374246E10

- anonymous

Not quite. What do you have before you plug it in?

- anonymous

i did 1^2-4(6)(-5) and i recieved 121 but then i raised that to the 5th power and i got that wierd number

- anonymous

but then instead of that i subtracted -5 then i divided by 12 and i got 10.5

- anonymous

?

- anonymous

why did you raise to the 5th. I said .5 or 0.5 or 1/2

- anonymous

that's probably the issue.

- anonymous

i still dnt get it i'm sorry for wasting your time!

- anonymous

Your calculator doesn't have a square root button?

- anonymous

it does but it is a blue sign above the X^2 button i cnt seem to get the sign but i always get the X^2

- anonymous

?

- anonymous

What kind of calculator do you have

- anonymous

a TI-84 PLUS SILVER ADDITION

- anonymous

Do you see the blue func button? Press that first, then press the x^2 button.

- anonymous

err should say 2nd on it.

- anonymous

I GOT IT! yah thanx yu

- anonymous

i got a -48

- anonymous

The square root of 121 is 11

- anonymous

So you should have
\[x = \frac{-1 \pm 11}{2(6)}\]

- anonymous

i feel so dum sorry!

- anonymous

sorry

- anonymous

hrm?

- anonymous

i got 32and -34 do i put down both of my answers

- anonymous

How do you get that?

- anonymous

-1 + 11 = 10
-1 - 11 = -12
So you should have 10/12 and -12/12 = -1

- anonymous

omg! im sorry but im dne i cnt do this!

- anonymous

I don't understand what's confusing you.

- anonymous

If you can explain I can try to help.

- anonymous

i just dont know how to do this im basically confused about evrything i dnt know what else to do

- anonymous

Well hang on.

- anonymous

Can you simplify the expression
\[\frac{4+3}{8}\]

- anonymous

7/8

- anonymous

1.142857143?

- anonymous

no im sorry 7/8

- anonymous

u k i have no idea wat ur sayin im in 5th grade
'

- anonymous

?

- anonymous

Yes, 7/8 is correct

- anonymous

Now try this one:
\[\frac{4-3}{2(4)}\]

- anonymous

polpok ur awesome

- anonymous

heh, thanks.

- anonymous

np

- anonymous

When working with fractions like this, just try to simplify the top and bottom separately.

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