anonymous
  • anonymous
how can i solve a quadratic equation like this 6x^2-5+x=0
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
rewrite it in the normal form and plug into the quadratic equation: \[ax^2 + bx + c = 0 \implies x = \frac{-(b) \pm \sqrt{(b)^2-4(a)(c)}}{2(a)}\]
anonymous
  • anonymous
thank you i did that part but where i am getting cofused at is that addition/ subtraction sign i dont kno what to do with it sorry i didnt say that earlier
anonymous
  • anonymous
Oh, well unless the part under the square root is 0 you will get 2 different possible solutions. \[x = \frac{-(b) + \sqrt{(b)^2-4(a)(c)}}{2(a)}\] and \[x = \frac{-(b) - \sqrt{(b)^2-4(a)(c)}}{2(a)}\] The \(\pm\) thing just makes it easier to write.

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anonymous
  • anonymous
oh ok thank you i'ma try it now :D
anonymous
  • anonymous
HOW WOUD I GET THAT SQUARE ROOT SYMBOL ON THE CALCULATOR
anonymous
  • anonymous
It should have it. If not you can raise it to the .5 power.
anonymous
  • anonymous
LIKE THIS (1^2-4(6)(-5)^5
anonymous
  • anonymous
it gave me some crazy number how would you do it i guess i was wrong
anonymous
  • anonymous
i got 2.59374246E10
anonymous
  • anonymous
Not quite. What do you have before you plug it in?
anonymous
  • anonymous
i did 1^2-4(6)(-5) and i recieved 121 but then i raised that to the 5th power and i got that wierd number
anonymous
  • anonymous
but then instead of that i subtracted -5 then i divided by 12 and i got 10.5
anonymous
  • anonymous
?
anonymous
  • anonymous
why did you raise to the 5th. I said .5 or 0.5 or 1/2
anonymous
  • anonymous
that's probably the issue.
anonymous
  • anonymous
i still dnt get it i'm sorry for wasting your time!
anonymous
  • anonymous
Your calculator doesn't have a square root button?
anonymous
  • anonymous
it does but it is a blue sign above the X^2 button i cnt seem to get the sign but i always get the X^2
anonymous
  • anonymous
?
anonymous
  • anonymous
What kind of calculator do you have
anonymous
  • anonymous
a TI-84 PLUS SILVER ADDITION
anonymous
  • anonymous
Do you see the blue func button? Press that first, then press the x^2 button.
anonymous
  • anonymous
err should say 2nd on it.
anonymous
  • anonymous
I GOT IT! yah thanx yu
anonymous
  • anonymous
i got a -48
anonymous
  • anonymous
The square root of 121 is 11
anonymous
  • anonymous
So you should have \[x = \frac{-1 \pm 11}{2(6)}\]
anonymous
  • anonymous
i feel so dum sorry!
anonymous
  • anonymous
sorry
anonymous
  • anonymous
hrm?
anonymous
  • anonymous
i got 32and -34 do i put down both of my answers
anonymous
  • anonymous
How do you get that?
anonymous
  • anonymous
-1 + 11 = 10 -1 - 11 = -12 So you should have 10/12 and -12/12 = -1
anonymous
  • anonymous
omg! im sorry but im dne i cnt do this!
anonymous
  • anonymous
I don't understand what's confusing you.
anonymous
  • anonymous
If you can explain I can try to help.
anonymous
  • anonymous
i just dont know how to do this im basically confused about evrything i dnt know what else to do
anonymous
  • anonymous
Well hang on.
anonymous
  • anonymous
Can you simplify the expression \[\frac{4+3}{8}\]
anonymous
  • anonymous
7/8
anonymous
  • anonymous
1.142857143?
anonymous
  • anonymous
no im sorry 7/8
anonymous
  • anonymous
u k i have no idea wat ur sayin im in 5th grade '
anonymous
  • anonymous
?
anonymous
  • anonymous
Yes, 7/8 is correct
anonymous
  • anonymous
Now try this one: \[\frac{4-3}{2(4)}\]
anonymous
  • anonymous
polpok ur awesome
anonymous
  • anonymous
heh, thanks.
anonymous
  • anonymous
np
anonymous
  • anonymous
When working with fractions like this, just try to simplify the top and bottom separately.

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