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anonymous
 5 years ago
(h(t)=16t^2+vt+c where h is the approximate height in ft t is the time in motion in seconds v is the initial upward velocity in ft per second and c is the initial height in ft)
A baseball player hits a pitched ball when it is 4ft above the ground the initial upward velocity is 80ft/s how long will it take for the ball to hit the ground???
anonymous
 5 years ago
(h(t)=16t^2+vt+c where h is the approximate height in ft t is the time in motion in seconds v is the initial upward velocity in ft per second and c is the initial height in ft) A baseball player hits a pitched ball when it is 4ft above the ground the initial upward velocity is 80ft/s how long will it take for the ball to hit the ground???

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0since H(t) is the height of the ball at a certain time, and you want to know the time at height 0 (when it hits the ground), set H(t) to 0. Then plug in the known values and solve for t

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u trying 2 make dat seem easy but it wont work try it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay, so we set the left side to 0, and plug in the values we know: V=80, C= 4. your equation at this point should be 16t^2+80t+4=0. Now all thats left is to isolate t by simplifying the expression and then solving. Hope this helps

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i simplified and got 0=4t^2+20t+1 do i figure out wat the time is
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