When a certain spring is expanded 6 centimeters from its natural position and held fixed, the force necessary to hold it is 1200 dynes. Find the work W required to stretch the spring an additional 6 centimeters.

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When a certain spring is expanded 6 centimeters from its natural position and held fixed, the force necessary to hold it is 1200 dynes. Find the work W required to stretch the spring an additional 6 centimeters.

Mathematics
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What's the spring constant?
Never mind you can calculate it with the given information
I tried \[\int\limits_{0}^{6} (k x)dx=1200 \] \[k*(6^2/2)=1200 \] So that k=200/3

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The force on a spring is F= k (d1 - d0) we say d0=0 and d1 is 6 cm so 1200= k * 6 200= k F= k ( d1- d0) where d1 is 12 cm and d0 is 6 cm F to stretch additional 6 cm is 200* 6 F= 1200 where work is F* change in distance we changed the distance by 6 cm so it should be 1200 * 6= 7200
I solved this with the knowledge I have in physics so this might not be what your teacher wants to see.
Thank you I'll try it out
Physics is a useful tool in mathematics: it explains a lot; math concentrates on the calculations.

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