Need help.....

- anonymous

Need help.....

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- anonymous

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- anonymous

Get the second function in respect to y like the first one and graph them.

- anonymous

Since you have to create a rectangle with another point and the two functions you can predict that the functions will be perpendicular to each other

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## More answers

- anonymous

are you having trouble graphing the functions?

- anonymous

is slope -2
yeah

- anonymous

\[2y + x= 2\]
\[2y + x - x= 2 -x\]
\[2y = 2 -x \]
\[2y/2 = (2 -x)/2 \]
\[y = 2/2-x/2\]
\[y = 1-(x/2)\]

- anonymous

perpendicular functions have inverse slopes.

- anonymous

is it something like this lol

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- anonymous

that's a triangle not a rectangle -.-

- anonymous

my bad i thought it said triangle lol

- anonymous

let me try again

- anonymous

idk

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- anonymous

nah i did it wrong try again

- anonymous

this one i hope

- anonymous

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- anonymous

i give up thats not right either dont look right i did -3 instead of 3

- anonymous

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- anonymous

both are wrong. The second one shows that they are parallel but they are perpendicular while the first one shows that x=a and y=b where both a and b are constants which is not the case here. If you are having trouble graphing try plotting some points
try plotting some points make a table
if X= 1,0,-1 what is y? do this for both

- anonymous

If you plug in X=0 what do you get in function 1 and 2?

- anonymous

2

- anonymous

show me your work

- anonymous

do i subtract 2x from both sides?

- anonymous

no Im asking you what happens when X=0

- anonymous

idk im lost

- anonymous

Are you taking pre-algebra?

- anonymous

algebra 1

- anonymous

if you have y= 2x + 1 and you plug in 0 for x what does y equal?

- anonymous

3

- anonymous

why is that?

- anonymous

is 2 * x or 2+x?

- anonymous

2+0=2+1=3

- anonymous

where did you get that 2+0 from?

- anonymous

its y = (2*x) + 1 solve that when you have x=0

- anonymous

answr 1

- anonymous

Do the same for the other function

- anonymous

answr 2

- anonymous

that's wrong please show work to see where you went wrong

- anonymous

2*0+0=2

- anonymous

no you said y= o in that equation
please look above in the equation I have and solve for y when x=0

- anonymous

is it 1

- anonymous

point (1,3)

- anonymous

Nope wrong. Sorry man I can't help you

- anonymous

ok im a girl thanks anyway

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