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anonymous
 5 years ago
Need help.....
anonymous
 5 years ago
Need help.....

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Get the second function in respect to y like the first one and graph them.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Since you have to create a rectangle with another point and the two functions you can predict that the functions will be perpendicular to each other

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you having trouble graphing the functions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2y + x= 2\] \[2y + x  x= 2 x\] \[2y = 2 x \] \[2y/2 = (2 x)/2 \] \[y = 2/2x/2\] \[y = 1(x/2)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0perpendicular functions have inverse slopes.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it something like this lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's a triangle not a rectangle .

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0my bad i thought it said triangle lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nah i did it wrong try again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i give up thats not right either dont look right i did 3 instead of 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0both are wrong. The second one shows that they are parallel but they are perpendicular while the first one shows that x=a and y=b where both a and b are constants which is not the case here. If you are having trouble graphing try plotting some points try plotting some points make a table if X= 1,0,1 what is y? do this for both

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you plug in X=0 what do you get in function 1 and 2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do i subtract 2x from both sides?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no Im asking you what happens when X=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you taking prealgebra?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you have y= 2x + 1 and you plug in 0 for x what does y equal?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where did you get that 2+0 from?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its y = (2*x) + 1 solve that when you have x=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do the same for the other function

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's wrong please show work to see where you went wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no you said y= o in that equation please look above in the equation I have and solve for y when x=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Nope wrong. Sorry man I can't help you

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok im a girl thanks anyway
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