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Get the second function in respect to y like the first one and graph them.
Since you have to create a rectangle with another point and the two functions you can predict that the functions will be perpendicular to each other
are you having trouble graphing the functions?
is slope -2 yeah
\[2y + x= 2\] \[2y + x - x= 2 -x\] \[2y = 2 -x \] \[2y/2 = (2 -x)/2 \] \[y = 2/2-x/2\] \[y = 1-(x/2)\]
perpendicular functions have inverse slopes.
that's a triangle not a rectangle -.-
my bad i thought it said triangle lol
let me try again
nah i did it wrong try again
this one i hope
i give up thats not right either dont look right i did -3 instead of 3
both are wrong. The second one shows that they are parallel but they are perpendicular while the first one shows that x=a and y=b where both a and b are constants which is not the case here. If you are having trouble graphing try plotting some points try plotting some points make a table if X= 1,0,-1 what is y? do this for both
If you plug in X=0 what do you get in function 1 and 2?
show me your work
do i subtract 2x from both sides?
no Im asking you what happens when X=0
idk im lost
Are you taking pre-algebra?
if you have y= 2x + 1 and you plug in 0 for x what does y equal?
why is that?
is 2 * x or 2+x?
where did you get that 2+0 from?
its y = (2*x) + 1 solve that when you have x=0
Do the same for the other function
that's wrong please show work to see where you went wrong
no you said y= o in that equation please look above in the equation I have and solve for y when x=0
is it 1
Nope wrong. Sorry man I can't help you
ok im a girl thanks anyway