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anonymous
 5 years ago
if f is one to one find an equation for its inverse
f(x)= 6/x3 and f(x) = sqr(x+1) x > 1
anonymous
 5 years ago
if f is one to one find an equation for its inverse f(x)= 6/x3 and f(x) = sqr(x+1) x > 1

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myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0the first f(x)=6/(x3) or 6/x3?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first is f(x) = 6/(x3)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0ok so do you know how you would solve for x?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0solve for x, why do we need to solve for x, should we put (x3)=0 ?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.0no to find inverse all you have to do is solve for x and when you get done doing this replace x with f^{1}(x) and replace f(x)=y with x ok y=6/(x3) multiply both sides by x3 y(x3)=6 yx3y=6 yx=6+3y x=(6+3y)/y f^{1})(x)=(6+3x)/x

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.02nd second one we have y=sqrt(x+1) square both sides y^2=x+1 subtract 1 y^21=x x=y^21 f^{1}(x)=x^21

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you very much, really appreciate that
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