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anonymous

  • 5 years ago

Just want to be sure I am doing this right... ln4x=6...

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  1. anonymous
    • 5 years ago
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    \[4^6=x\]

  2. anonymous
    • 5 years ago
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    Or x=16384

  3. anonymous
    • 5 years ago
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    That seems way too large to be right.

  4. anonymous
    • 5 years ago
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    It's incorrect x = 4096

  5. anonymous
    • 5 years ago
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    but ln 4x = 6 is 4x = e^6 x = e^6 / 4

  6. anonymous
    • 5 years ago
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    so its not 4^6

  7. anonymous
    • 5 years ago
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    Wait, how so?

  8. anonymous
    • 5 years ago
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    I agree with x = e^6 / 4, but thenwhy does x = 4096?

  9. anonymous
    • 5 years ago
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    it's not. 4^6 = 4096.

  10. anonymous
    • 5 years ago
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    But aren't you supposed to get rid of a log in order to solve for x?

  11. anonymous
    • 5 years ago
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    lnx means log base e of x so ln4x = log(base e)4x

  12. anonymous
    • 5 years ago
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    I know ln has a base of e, and that would be \[e^4x=6\]

  13. anonymous
    • 5 years ago
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    it messed up, one sec

  14. anonymous
    • 5 years ago
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    nvm, it won't let me do it. e^(4x)=6 is what I was trying to say

  15. anonymous
    • 5 years ago
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    Eh, I still don't get this. Could you rewrite this as \[e^6=4x\]

  16. anonymous
    • 5 years ago
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    divide both sides by 4, and you get: \[e^6/4=x\]

  17. anonymous
    • 5 years ago
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    which is exactly what you said...

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spraguer (Moderator)
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