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anonymous
 5 years ago
Just want to be sure I am doing this right...
ln4x=6...
anonymous
 5 years ago
Just want to be sure I am doing this right... ln4x=6...

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That seems way too large to be right.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's incorrect x = 4096

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but ln 4x = 6 is 4x = e^6 x = e^6 / 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I agree with x = e^6 / 4, but thenwhy does x = 4096?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's not. 4^6 = 4096.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But aren't you supposed to get rid of a log in order to solve for x?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lnx means log base e of x so ln4x = log(base e)4x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know ln has a base of e, and that would be \[e^4x=6\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it messed up, one sec

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nvm, it won't let me do it. e^(4x)=6 is what I was trying to say

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Eh, I still don't get this. Could you rewrite this as \[e^6=4x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0divide both sides by 4, and you get: \[e^6/4=x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which is exactly what you said...
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