anonymous
  • anonymous
Just want to be sure I am doing this right... ln4x=6...
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
\[4^6=x\]
anonymous
  • anonymous
Or x=16384
anonymous
  • anonymous
That seems way too large to be right.

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anonymous
  • anonymous
It's incorrect x = 4096
anonymous
  • anonymous
but ln 4x = 6 is 4x = e^6 x = e^6 / 4
anonymous
  • anonymous
so its not 4^6
anonymous
  • anonymous
Wait, how so?
anonymous
  • anonymous
I agree with x = e^6 / 4, but thenwhy does x = 4096?
anonymous
  • anonymous
it's not. 4^6 = 4096.
anonymous
  • anonymous
But aren't you supposed to get rid of a log in order to solve for x?
anonymous
  • anonymous
lnx means log base e of x so ln4x = log(base e)4x
anonymous
  • anonymous
I know ln has a base of e, and that would be \[e^4x=6\]
anonymous
  • anonymous
it messed up, one sec
anonymous
  • anonymous
nvm, it won't let me do it. e^(4x)=6 is what I was trying to say
anonymous
  • anonymous
Eh, I still don't get this. Could you rewrite this as \[e^6=4x\]
anonymous
  • anonymous
divide both sides by 4, and you get: \[e^6/4=x\]
anonymous
  • anonymous
which is exactly what you said...

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