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anonymous

  • 5 years ago

Solve: 2x+3y+z=-3 x+4y-3z=-23 3x-y+2z=14

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  1. anonymous
    • 5 years ago
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    do you know how to use matrix or just algebra...?

  2. anonymous
    • 5 years ago
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    Algebra

  3. anonymous
    • 5 years ago
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    I looked at this thing and decided to use Mathematica to solve it. \[\text{Solve}[\{2x+3y+z\text{==}-3, x+4y-3z\text{==}-23 ,3x-y+2z\text{==}14\},\{x,y,z\}] \]={{x -> 1, y -> -3, z -> 4}} Feeding the solutions for x, y and z back into the equations show that they are the roots. \[\{2x+3y+z\text{=}-3, x+4y-3z\text{=}-23 ,3x-y+2z\text{=}14\}\text{/.}\{x\to 1,y\to -3,z\to 4\} \]={True, True, True} True means that the left hand side and the right hand side of each equation is equal.

  4. anonymous
    • 5 years ago
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    Mathematica can deal with matix expressions, however, I cannot. In the case of these three equations the setup is much easier to use Solve rather than LinearSolve. Sorry.

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