## anonymous 5 years ago Solve: 2x+3y+z=-3 x+4y-3z=-23 3x-y+2z=14

1. anonymous

do you know how to use matrix or just algebra...?

2. anonymous

Algebra

3. anonymous

I looked at this thing and decided to use Mathematica to solve it. $\text{Solve}[\{2x+3y+z\text{==}-3, x+4y-3z\text{==}-23 ,3x-y+2z\text{==}14\},\{x,y,z\}]$={{x -> 1, y -> -3, z -> 4}} Feeding the solutions for x, y and z back into the equations show that they are the roots. $\{2x+3y+z\text{=}-3, x+4y-3z\text{=}-23 ,3x-y+2z\text{=}14\}\text{/.}\{x\to 1,y\to -3,z\to 4\}$={True, True, True} True means that the left hand side and the right hand side of each equation is equal.

4. anonymous

Mathematica can deal with matix expressions, however, I cannot. In the case of these three equations the setup is much easier to use Solve rather than LinearSolve. Sorry.