Find an equation of a line parallel to the line 3x-2y=4 and containing the point (3,-5)
Stacey Warren - Expert brainly.com
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\[2y=4\]is this wat u tryin to find
parallel = means the same slope
re-write your ew as:
2y=3x-4 or y=3/2 x -2
so, slope your existing line is: m=3/2
so, eq of parallel through the point (3,5):
y=3/2x -9/2 +5=3/2 x+1/2
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That makes sense.... Thank you!
Can you help me with another one?
shoot... I need to go soon
Its like the one you just helped me with only perpendicular to the line 3x-2y=4 and containing points 3,-5
try to do it yourself - I'll help.
just remember that perpendicular means that your line will have slope (m2) = -1/m1...
so, if re-write your eq:
y=3/2 x -2
so, for perp line: m2=-2/3
eq of the line:
So then y=-2/3x+6/3-5?
y+5=-2/3 *x +2
y=-2/3 *x -3
do you see it?
So the equation is y=-2/3x-3?
yep... to be exact:
y=(-2x/3 ) -3
Okay, I guess I just don't get how you suddenly got to x+2 in the end
let's go back to:
i think that the way it written it could be confusing... let's try differently:
y+5= x* (-2/3) -3* (-2/3)
y+5=-2x/3 +2 (-3 in numerator & -3 in dominator are canceled out)
is it better...?
That does make better sense. Math is like a whole other language for me, lol. Thank you so much for your help