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- anonymous

Find an equation of a line parallel to the line 3x-2y=4 and containing the point (3,-5)

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- anonymous

Find an equation of a line parallel to the line 3x-2y=4 and containing the point (3,-5)

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- anonymous

\[2y=4\]is this wat u tryin to find

- anonymous

yes

- anonymous

parallel = means the same slope
re-write your ew as:
2y=3x-4 or y=3/2 x -2
so, slope your existing line is: m=3/2
so, eq of parallel through the point (3,5):
y-5=3/2 *(x-3)
y=3/2x -9/2 +5=3/2 x+1/2

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- anonymous

That makes sense.... Thank you!

- anonymous

Can you help me with another one?

- anonymous

shoot... I need to go soon

- anonymous

Its like the one you just helped me with only perpendicular to the line 3x-2y=4 and containing points 3,-5

- anonymous

try to do it yourself - I'll help.
just remember that perpendicular means that your line will have slope (m2) = -1/m1...
so, if re-write your eq:
y=3/2 x -2
so, for perp line: m2=-2/3
eq of the line:
y-(-5)=-2/3 (x-3)
simplify, please

- anonymous

So then y=-2/3x+6/3-5?

- anonymous

y+5=-2/3 *x +2
y=-2/3 *x -3

- anonymous

do you see it?

- anonymous

So the equation is y=-2/3x-3?

- anonymous

yep... to be exact:
y=(-2x/3 ) -3

- anonymous

Okay, I guess I just don't get how you suddenly got to x+2 in the end

- anonymous

let's go back to:
y-(-5)=-2/3 (x-3)
i think that the way it written it could be confusing... let's try differently:
y+5= x* (-2/3) -3* (-2/3)
y+5=-2x/3 +2 (-3 in numerator & -3 in dominator are canceled out)
is it better...?

- anonymous

That does make better sense. Math is like a whole other language for me, lol. Thank you so much for your help

- anonymous

Great! Welcome :)

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