anonymous
  • anonymous
Find an equation of a line parallel to the line 3x-2y=4 and containing the point (3,-5)
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[2y=4\]is this wat u tryin to find
anonymous
  • anonymous
yes
anonymous
  • anonymous
parallel = means the same slope re-write your ew as: 2y=3x-4 or y=3/2 x -2 so, slope your existing line is: m=3/2 so, eq of parallel through the point (3,5): y-5=3/2 *(x-3) y=3/2x -9/2 +5=3/2 x+1/2

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anonymous
  • anonymous
That makes sense.... Thank you!
anonymous
  • anonymous
Can you help me with another one?
anonymous
  • anonymous
shoot... I need to go soon
anonymous
  • anonymous
Its like the one you just helped me with only perpendicular to the line 3x-2y=4 and containing points 3,-5
anonymous
  • anonymous
try to do it yourself - I'll help. just remember that perpendicular means that your line will have slope (m2) = -1/m1... so, if re-write your eq: y=3/2 x -2 so, for perp line: m2=-2/3 eq of the line: y-(-5)=-2/3 (x-3) simplify, please
anonymous
  • anonymous
So then y=-2/3x+6/3-5?
anonymous
  • anonymous
y+5=-2/3 *x +2 y=-2/3 *x -3
anonymous
  • anonymous
do you see it?
anonymous
  • anonymous
So the equation is y=-2/3x-3?
anonymous
  • anonymous
yep... to be exact: y=(-2x/3 ) -3
anonymous
  • anonymous
Okay, I guess I just don't get how you suddenly got to x+2 in the end
anonymous
  • anonymous
let's go back to: y-(-5)=-2/3 (x-3) i think that the way it written it could be confusing... let's try differently: y+5= x* (-2/3) -3* (-2/3) y+5=-2x/3 +2 (-3 in numerator & -3 in dominator are canceled out) is it better...?
anonymous
  • anonymous
That does make better sense. Math is like a whole other language for me, lol. Thank you so much for your help
anonymous
  • anonymous
Great! Welcome :)

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