Divide: (3x^3+2x^2-x-10) / (x+2)

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Divide: (3x^3+2x^2-x-10) / (x+2)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Quotient is \[3x ^{2} - 4x + 7\] and remainder is -24
How did you get that though?
Is it correct???

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yes
okay I will show the working It is by the LONG DIVISION METHOD as follows: 3x^2 - 4x + 7 ------------------------ x+2 | 3x^3 + 2x^2 - x - 10 -3x^3 - 6x^2 ---------------------- -4x^2 - x - 10 +4x^2 +8x --------------- 7x - 10 -7x - 14 ---------- - 24 Is that clear enough???
yes thank you
Got a medal for me??
Mathematica confirms that Harkirat is correct. \[\text{PolynomialQuotient}\left[-10-x+2 x^2+3 x^3,2+x,x\right]=7-4 x+3 x^2 \] \[\text{PolynomialRemainder}\left[-10-x+2 x^2+3 x^3,2+x,x\right] =-24\] Congratulations Harkirat. It has been alot years since I've seen that done by hand. Very interesting.

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