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anonymous

  • 5 years ago

Can anyone explain how the system of an electron placed outside of a ring of charge undergoes simple harmonic motion? I am asked to setup a SHM differential equation for a system that looks like this: http://people.rit.edu/agysps/courses/313_071web/class_wksheets/INTring_low.gif where P is an electron.

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  1. anonymous
    • 5 years ago
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    if an electron is placed along the axis of a positively charged ring, u can see the equation of the force acting on it is directly proportional to x, the distance from the ring, after neglecting certain values.

  2. anonymous
    • 5 years ago
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    F= -kpq(x)/\[(R^{2} + x^{2})^{3/2}\]

  3. anonymous
    • 5 years ago
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    if R>>x we get F= \[-kpq (x) / R^3\]

  4. anonymous
    • 5 years ago
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    a = -kpx/mr^3

  5. anonymous
    • 5 years ago
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    \[d ^{2}x/dt^{2}\] = -(kpq / R^3)(x)

  6. anonymous
    • 5 years ago
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    ?

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