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anonymous

  • 5 years ago

hi how do i enter my problem?

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  1. anonymous
    • 5 years ago
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    type it in hun if u = girl

  2. anonymous
    • 5 years ago
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    ok i got it. \[\sqrt[4]{x ^{3}y}+\sqrt{9y ^{3}}\]

  3. anonymous
    • 5 years ago
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    that didnt work. hold on. sorry

  4. anonymous
    • 5 years ago
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    how do i do complex equations and type them in correctly?

  5. anonymous
    • 5 years ago
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    HELP?

  6. anonymous
    • 5 years ago
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    ok u could write that like this: cuberoot(x^3 *y) + sqrtroot(9y^3)

  7. anonymous
    • 5 years ago
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    bummer.. ok. ill try another one.. x^2+5x is less than or equal to 6

  8. anonymous
    • 5 years ago
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    yeah thats it

  9. anonymous
    • 5 years ago
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    or x^2 + 5x >= 6 but the worded one is okay, the key is to ask the question as best u can so that the person can understand

  10. anonymous
    • 5 years ago
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    ok well that is my question.. can you help me with it please

  11. anonymous
    • 5 years ago
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    ok

  12. anonymous
    • 5 years ago
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    it would be -6 less than or equal to x less than or equal to 1

  13. anonymous
    • 5 years ago
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    so x^2+5x<= 6 x^2 + 5x - 6 <= 0 (x+6)(x-1) -6<=x<=1

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spraguer (Moderator)
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