A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
how can I delete indetermination in the following expression.
Limx(x>0)((sqrt(x+2)sqrt(2))/x)
anonymous
 5 years ago
how can I delete indetermination in the following expression. Limx(x>0)((sqrt(x+2)sqrt(2))/x)

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[limit _{x>0}(\sqrt{x+2}\sqrt{2})/2\] this is the equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0limitx−>0(x+2−−−−−√−2−−√)/x Sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you mean by multiplyting the numerator and the denominator by \[\sqrt{x+2}+\sqrt{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Changuanas, I actually get rid of indetermination. However when I apply the limit x>0, the answer is not the corrrect. The answer int he book is 1/2sqrt(2).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry. I was wrong. I already got the answer! Can you help me with another exercise? Just to check

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just post question, if fall asleep someone else would help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[Limit _{x>infinity} \sqrt{3x ^{4}2x+4}+x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't remember what happens to infinity under square root. Does it go to infinity?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0According to the graph, it increases with no bound

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ignore all others and consider only highest exponent of x. What is highest exp?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm sorry. Did you already have an answer: infinity? or it needs more work?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think the answer is 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is highest exponent x in your problem?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0inside the root? its 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ignore all others divide sq rt 3x^4 by sq rt x^4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wouldn't that one have to be just infinity?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think he is in an early class. The class before you study infinity, right Emun?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In that case, don't ignore everything else, that is what you do in higher math;keep everything and divide each term by x^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's funny being all done finals but still here during my break lol. why am I here?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0except that expression isn't anything you would need to do that for. maybe if you were dividing by a polynomial

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You here to help Emun I'm going to sleep.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0guys the equation was wrong. The equation is the following: \[\sqrt{x ^{2}2x+4}+x\] I factored the expression inside the root out and I got \[\sqrt{(x2)^{2}}+x\] so finally I got \[x2+x\] as I apply the limit as x=infinity,the answer I got is 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The answer would be infinity, wouldn't it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wouldn't you get 2x2 , which as x becomes large.. your expression does too? infinity!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah and this is the answer: Thanks gusy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 0} (\sqrt{x+2}\sqrt{2})/x \times (\sqrt{x+2}+\sqrt{2})/(\sqrt{x+2}+\sqrt{2})\] \[\lim_{x \rightarrow 0} (x+22)/(x(\sqrt{x+2}+\sqrt{2}))\] \[\lim_{x \rightarrow 0} x/(x(\sqrt{x+2}+\sqrt{2}))\] \[\lim_{x \rightarrow 0} 1/(\sqrt{x+2}+\sqrt{2})\] \[1/(\sqrt{0+2}+\sqrt{2})\] \[1/(\sqrt{2}+\sqrt{2})\] \[1/(2\sqrt{2})\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.