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\[limit _{x->0}(\sqrt{x+2}-\sqrt{2})/2\] this is the equation

conjugation

limitx−>0(x+2−−−−−√−2−−√)/x Sorry

you mean by multiplyting the numerator and the denominator by \[\sqrt{x+2}+\sqrt{2}\]

Top and bottom

ok let me try

Sorry. I was wrong. I already got the answer! Can you help me with another exercise? Just to check

just post question, if fall asleep someone else would help

\[Limit _{x->infinity} \sqrt{3x ^{4}-2x+4}+x\]

I don't remember what happens to infinity under square root. Does it go to infinity?

According to the graph, it increases with no bound

Ignore all others and consider only highest exponent of x. What is highest exp?

I'm sorry. Did you already have an answer: infinity? or it needs more work?

yes, more work :)

I think the answer is 1

what is highest exponent x in your problem?

inside the root? its 2

Ignore all others divide sq rt 3x^4 by sq rt x^4

Wouldn't that one have to be just infinity?

I think he is in an early class. The class before you study infinity, right Emun?

yes

It's funny being all done finals but still here during my break lol. why am I here?

You here to help Emun I'm going to sleep.

Thanks changaunas :)

The answer would be infinity, wouldn't it?

wouldn't you get 2x-2 , which as x becomes large.. your expression does too?
infinity!

Yeah and this is the answer: Thanks gusy

thanks guys :)