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anonymous

  • 5 years ago

can anyone help me with solving problems with Exponential and Logarithmic

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  1. anonymous
    • 5 years ago
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    Yes where are the questions

  2. amistre64
    • 5 years ago
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    yes

  3. anonymous
    • 5 years ago
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    Solve this equation for x. Round your answer to the nearest hundredth. 0.59 = log x

  4. amistre64
    • 5 years ago
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    assuming log is base 10

  5. amistre64
    • 5 years ago
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    10^.59 = x

  6. anonymous
    • 5 years ago
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    i got 3.890

  7. amistre64
    • 5 years ago
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    that is correct... or so the calculator tells me :)

  8. anonymous
    • 5 years ago
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    6 = In(x+4)

  9. amistre64
    • 5 years ago
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    e^6 = x+4 e^6 -4 = x

  10. anonymous
    • 5 years ago
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    399.427?

  11. amistre64
    • 5 years ago
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    thats correct

  12. anonymous
    • 5 years ago
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    now.. here is a type i'm stuck on

  13. anonymous
    • 5 years ago
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    You invest $4200 in an account that pays an interest rate of 6.5%, compounded continuously. Calculate the balance of your account in 10 years. round your answer to the nearest hundredth

  14. amistre64
    • 5 years ago
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    to compound continuosly means we use pert for our answer.. 4200(e^(.065)(10))

  15. anonymous
    • 5 years ago
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    80452.680?

  16. amistre64
    • 5 years ago
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    8045.271 is what i get... but i have no 'e' button

  17. anonymous
    • 5 years ago
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    e generally equal 2.71828

  18. amistre64
    • 5 years ago
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    2.71828182845905.... :)

  19. amistre64
    • 5 years ago
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    4200(e^.65)

  20. anonymous
    • 5 years ago
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    for that i got 8045.268

  21. amistre64
    • 5 years ago
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    you got a choice of answers to go from?

  22. anonymous
    • 5 years ago
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    no. i have to type in an answer

  23. amistre64
    • 5 years ago
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    does the material you are working from give you an approximation for 'e' to use?

  24. anonymous
    • 5 years ago
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    no but i searched it & was also told that almost every time e = 2.71828

  25. amistre64
    • 5 years ago
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    4200 * (e^.65) = 8045.27148 when i type it into google, the calc pops this out...

  26. amistre64
    • 5 years ago
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    id go with: 8045.27 or .28

  27. anonymous
    • 5 years ago
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    i went with .27

  28. anonymous
    • 5 years ago
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    nextt question: holly wants to save money for an emergency. holly invests $1200 in an account that pays an interest rate of 4%. how many years will it take for the account to reach $15,400? round your answer to the nearest hundredth

  29. shadowfiend
    • 5 years ago
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    Remember to give amistre a medal if they helped you out!

  30. anonymous
    • 5 years ago
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    was already planning on doing that

  31. anonymous
    • 5 years ago
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    4% interest is SIMPLE INTEREST or COMPOUND INTEREST???

  32. anonymous
    • 5 years ago
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    i really don't know. it doesn't say. some have said compounded continuously. but this one doesn't

  33. amistre64
    • 5 years ago
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    they can also forget to give me a medal.... i got plenty to spare ;)

  34. amistre64
    • 5 years ago
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    if its over a year, then compund interest is applied usually

  35. anonymous
    • 5 years ago
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    Using Simple Interest, the time comes out way too long, must be Compound interest

  36. amistre64
    • 5 years ago
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    savings accounts are usualy compounded yearly...

  37. anonymous
    • 5 years ago
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    i do believe it is compounded

  38. anonymous
    • 5 years ago
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    Pls check and reconfirm the numbers in the question. The given ones don't seem to b right

  39. anonymous
    • 5 years ago
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    those are correct

  40. anonymous
    • 5 years ago
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    The given numbers do not work for Compound interest So, for Simple interest, the answer is 295.83 years (Way too long!!??) This one beats me:( Anyone else take a shot at it??

  41. anonymous
    • 5 years ago
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    i'll post the question again as another question & see if anyone will answer it. i'm confused on these ones.

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