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anonymous

  • 5 years ago

can anyone help me with solving problems with Exponential and Logarithmic

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  1. anonymous
    • 5 years ago
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    whats the prob be?

  2. anonymous
    • 5 years ago
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    holly wants to save money for an emergency. holly invests $1200 in an account that pays an interest rate of 4%. how many years will it take for the account to reach $15,400? round your answer to the nearest hundredth

  3. amistre64
    • 5 years ago
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    15400=1200(1.04)^t

  4. amistre64
    • 5 years ago
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    154 ---- = 1.04^t 12

  5. amistre64
    • 5 years ago
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    t = log1.04(154/12)

  6. anonymous
    • 5 years ago
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    140.714 is what i got. correct?

  7. amistre64
    • 5 years ago
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    we can do change of base to be able to do this on a calculator...

  8. amistre64
    • 5 years ago
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    log(154/12) ---------- log(1.04)

  9. amistre64
    • 5 years ago
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    65.07 years?

  10. amistre64
    • 5 years ago
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    you can always double check by plugging your answer into the original...

  11. amistre64
    • 5 years ago
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    15400 ?=? 1200(1.04)^(65.07)

  12. amistre64
    • 5 years ago
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    15400.706

  13. anonymous
    • 5 years ago
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    so 65.07 is correct?

  14. amistre64
    • 5 years ago
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    i believe it is..... but i dont know how your program accepts its answers.... it may be off by 1/100

  15. anonymous
    • 5 years ago
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    it was right!

  16. amistre64
    • 5 years ago
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    yay!!

  17. anonymous
    • 5 years ago
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    You invest $4,900 in an account that pays an interest rate of 5.5%, compounded continuously. Calculate the balance of your account after 6 years. Round your answer to the nearest hundredth,

  18. amistre64
    • 5 years ago
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    cant get medals if no new questions are posted lol.....

  19. amistre64
    • 5 years ago
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    pert again....

  20. amistre64
    • 5 years ago
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    4900(e^(.055)(6))

  21. amistre64
    • 5 years ago
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    plug that into google and the calc will spit back an answer

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