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anonymous
 5 years ago
Find the specified nth term in the expansion of the binomial. (Write the expansion in descending powers of x.)
(x  4y)^6, n = 3
anonymous
 5 years ago
Find the specified nth term in the expansion of the binomial. (Write the expansion in descending powers of x.) (x  4y)^6, n = 3

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok so that's from pascal's triangle right... I sort of understand this but still a little confussed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11x^6 +6x^5y15x^4y20x^3y25x^2y6xy +y yes

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok so when I did this I was close but I mixed up the x and y components like x goes down and y goes up...?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11x^6 +6x^5(4y) +15x^4(4y)^2 +20x^3(4y)^3 +15x^2(4y)^4 +6x(4)^5 +(4)y^6

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1yes; the x descends as the y ascends

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just follow wat amistre says

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the 3rd term is: 15(16) x^4 y^2 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1lol..... unless we are heading for a cliff, then dont ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol ok can you explain where you are getting the third term after I fixed my x and y's and combined terms I got 6x(4)^5 +(4)y^6....what did you do from there?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1the 'y' component here is (4y)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.11,6,15...the coeff is gonna be 15 as a standard..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1x^6,5,4... y^0,1,2 15x^4 (4y)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh I see where you got that so if I simplified it it would be 240x^4y^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank you so much! This was a problem I sat here and was like what the heck am I doing wrong! lol thank you thank you thank you!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1just a moment of lucidity for me :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so I have (x  2y)^12, n = 6 1, 12, 66,220,495,792, 924,792,495,220,66,12,1 1x^12+12x^11y+66x^10y+220x^9y+495x^8y+792x^7y+924x^6y+792x^5y+495x^4y+495x^3y+220x^2y+66x^1y+12xy+1x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Idk if I did that right actually...?
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