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Once you have read the whole document there, you will very easily solve this problem
change to vectors and calculate...
Most probably the person is not acquainted to that method, that is why I have provided that link. Hope that will be helpful.
we add the vectors right?
for each vector
82 = b
111 = c
right I have that cause that's how my book sets it up... then I'm confused where to go from there cause I think my book skips a few steps explanation wise...
i get a vetor of<-18.4345,-48.06> which is just a point from the origin
when we add all the vectors together from head to tail we get a new vector that points n the direction of the angle and with a new magnitude
ok so that's what the <-18.4345,-48.06> is from....
our new vector
has a magnitude of sqrt(x^2 + y^2)
and a direction of tan^-1(y/x) + pi
so the direction is 72.156?
we add +pi because tan^-1 only spits out angles in Q1 and Q4; so we no we need Q3 which will be 180 degrees from the tan^-1
oh.. ok? I'm kinda lost thought I was following you but I don't think I am any more
teh shaded area is the range that tan^-1 operates in for define it as a function....
when you say so we now we need Q3 which will be 180 degrees from the tan^-1 do I take tan(180) or tan^-1(180)?
our angle is in -x,-y..... which is Q3
tan^-1(our angles x and y) spits us out in Q1... add 180 to that to get our answer
200.985 is what I get
but let me recheck my fingers lol
oh wow I'm way off the problem is neither of our answers match up with theirs.... ugh this dang practice test is gonna be the death of me! lol
tan^-1 spits out 20.9854
let me re check the vector addition.... i tend to mess that up alot :)
(52 * cos(100)) + (82 * cos(190)) + (111 * cos(310)) = -8.03584413 according to google
so thats our x coord
(52 * sin(100)) + (82 * sin(190)) + (111 * sin(310)) = 149.937061 google calculator again
so I take the tan^-1 of those and then add 180?
((52 * sin(100)) + (82 * sin(190)) + (111 * sin(310))) ------------------------------------------------ ((52 * cos(100)) + (82 * cos(190)) + (111 * cos(310))) = -18.6585328 so lets tan^-1 that amount
ohhh I see
the add 180 depends on where our angle is pointing; if its in Q1 or Q4 we are good; if not then add 180
with sin (+) and cos(-) we are in Q2 so add 180
so if I add the 180 I get 93.06781973
.......thats what I get too. its not telling you any more info is it
Nope I can show you my answer choices...
are your numbers right in the problem?
jk i forgot I posted the answer choices with them lol no everything is right I took it right from my practice exam online....
almost done :)
ha ha ok just let me know thanks for helping me out so much!
it doesn't show my anything just blank what numbers should I plug in?
just kidding I'll plugg in my original numbers from the problem
im working and mags v1.3 :)
ha ok....well idk I might just guess at it
....... either somethings missing in the problem like a gravity vector of a fr a friction vector.... or i forgot how to add :)
ha ha no I think something is missing in the problem and it's just not written right on the review.... oh well thanks sorry I took so much of your time
'sok....try PIs way...and see if you ge tthe same results...
oh Pi's way... wow I'm sorry you probably think i'm retarded or something lol
PI gave a website....you know, instead of conversing with you and such ;)
ha ha ya I read it lol my book gives me the same way we just tried it but I can try his way not sure if I understand it but I'll give it a shot thanks anyways!
woohoo....i got a 249 degrees
Ha ha thank you!