anonymous
  • anonymous
Three forces with magnitudes of 52 pounds, 82 pounds, and 111 pounds act on an object at angles 100o, 190o, and 310o, respectively, with the positive x-axis. Find the magnitude and direction of the resultant force. Round answers to two decimal places. A. 33.13 pounds; 69.01o B. 51.47 pounds; 249.01o C. 33.13 pounds; 249.01o D. 73.18 pounds; 280.53o E. 51.47 pounds; 69.01o
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
http://www.slideshare.net/stootypal/concurrent-forces-1653276
anonymous
  • anonymous
Once you have read the whole document there, you will very easily solve this problem
amistre64
  • amistre64
change to vectors and calculate...

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Most probably the person is not acquainted to that method, that is why I have provided that link. Hope that will be helpful.
amistre64
  • amistre64
we add the vectors right?
amistre64
  • amistre64
|M| for each vector
amistre64
  • amistre64
52 = a 82 = b 111 = c
anonymous
  • anonymous
right I have that cause that's how my book sets it up... then I'm confused where to go from there cause I think my book skips a few steps explanation wise...
amistre64
  • amistre64
i get a vetor of<-18.4345,-48.06> which is just a point from the origin
amistre64
  • amistre64
when we add all the vectors together from head to tail we get a new vector that points n the direction of the angle and with a new magnitude
anonymous
  • anonymous
ok so that's what the <-18.4345,-48.06> is from....
amistre64
  • amistre64
our new vector has a magnitude of sqrt(x^2 + y^2) and a direction of tan^-1(y/x) + pi
anonymous
  • anonymous
so the direction is 72.156?
amistre64
  • amistre64
we add +pi because tan^-1 only spits out angles in Q1 and Q4; so we no we need Q3 which will be 180 degrees from the tan^-1
anonymous
  • anonymous
oh.. ok? I'm kinda lost thought I was following you but I don't think I am any more
amistre64
  • amistre64
1 Attachment
amistre64
  • amistre64
teh shaded area is the range that tan^-1 operates in for define it as a function....
anonymous
  • anonymous
when you say so we now we need Q3 which will be 180 degrees from the tan^-1 do I take tan(180) or tan^-1(180)?
amistre64
  • amistre64
our angle is in -x,-y..... which is Q3
anonymous
  • anonymous
ok
amistre64
  • amistre64
tan^-1(our angles x and y) spits us out in Q1... add 180 to that to get our answer
anonymous
  • anonymous
90.86?
amistre64
  • amistre64
200.985 is what I get
amistre64
  • amistre64
but let me recheck my fingers lol
anonymous
  • anonymous
oh wow I'm way off the problem is neither of our answers match up with theirs.... ugh this dang practice test is gonna be the death of me! lol
amistre64
  • amistre64
tan^-1 spits out 20.9854
amistre64
  • amistre64
let me re check the vector addition.... i tend to mess that up alot :)
amistre64
  • amistre64
(52 * cos(100)) + (82 * cos(190)) + (111 * cos(310)) = -8.03584413 according to google
amistre64
  • amistre64
so thats our x coord
amistre64
  • amistre64
(52 * sin(100)) + (82 * sin(190)) + (111 * sin(310)) = 149.937061 google calculator again
anonymous
  • anonymous
so I take the tan^-1 of those and then add 180?
amistre64
  • amistre64
((52 * sin(100)) + (82 * sin(190)) + (111 * sin(310))) ------------------------------------------------ ((52 * cos(100)) + (82 * cos(190)) + (111 * cos(310))) = -18.6585328 so lets tan^-1 that amount
anonymous
  • anonymous
ohhh I see
anonymous
  • anonymous
-86.93218027
amistre64
  • amistre64
the add 180 depends on where our angle is pointing; if its in Q1 or Q4 we are good; if not then add 180
amistre64
  • amistre64
with sin (+) and cos(-) we are in Q2 so add 180
anonymous
  • anonymous
so if I add the 180 I get 93.06781973
amistre64
  • amistre64
.......thats what I get too. its not telling you any more info is it
anonymous
  • anonymous
Nope I can show you my answer choices...
amistre64
  • amistre64
are your numbers right in the problem?
amistre64
  • amistre64
no typos?
anonymous
  • anonymous
jk i forgot I posted the answer choices with them lol no everything is right I took it right from my practice exam online....
amistre64
  • amistre64
let me write up a quick javascript to help us..
anonymous
  • anonymous
ok
amistre64
  • amistre64
almost done :)
anonymous
  • anonymous
ha ha ok just let me know thanks for helping me out so much!
amistre64
  • amistre64
this is what i get, if its debbugged all the way
1 Attachment
anonymous
  • anonymous
it doesn't show my anything just blank what numbers should I plug in?
anonymous
  • anonymous
just kidding I'll plugg in my original numbers from the problem
amistre64
  • amistre64
...... ha.....ha
anonymous
  • anonymous
99.99?
amistre64
  • amistre64
im working and mags v1.3 :)
amistre64
  • amistre64
i know.......
anonymous
  • anonymous
ha ok....well idk I might just guess at it
amistre64
  • amistre64
....... either somethings missing in the problem like a gravity vector of a fr a friction vector.... or i forgot how to add :)
anonymous
  • anonymous
ha ha no I think something is missing in the problem and it's just not written right on the review.... oh well thanks sorry I took so much of your time
amistre64
  • amistre64
'sok....try PIs way...and see if you ge tthe same results...
anonymous
  • anonymous
say what?
anonymous
  • anonymous
oh Pi's way... wow I'm sorry you probably think i'm retarded or something lol
amistre64
  • amistre64
PI gave a website....you know, instead of conversing with you and such ;)
anonymous
  • anonymous
ha ha ya I read it lol my book gives me the same way we just tried it but I can try his way not sure if I understand it but I'll give it a shot thanks anyways!
amistre64
  • amistre64
woohoo....i got a 249 degrees
amistre64
  • amistre64
its B
anonymous
  • anonymous
Ha ha thank you!

Looking for something else?

Not the answer you are looking for? Search for more explanations.