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anonymous
 5 years ago
Three forces with magnitudes of 52 pounds, 82 pounds, and 111 pounds act on an object at angles 100o, 190o, and 310o, respectively, with the positive xaxis. Find the magnitude and direction of the resultant force. Round answers to two decimal places.
A. 33.13 pounds; 69.01o
B. 51.47 pounds; 249.01o
C. 33.13 pounds; 249.01o
D. 73.18 pounds; 280.53o
E. 51.47 pounds; 69.01o
anonymous
 5 years ago
Three forces with magnitudes of 52 pounds, 82 pounds, and 111 pounds act on an object at angles 100o, 190o, and 310o, respectively, with the positive xaxis. Find the magnitude and direction of the resultant force. Round answers to two decimal places. A. 33.13 pounds; 69.01o B. 51.47 pounds; 249.01o C. 33.13 pounds; 249.01o D. 73.18 pounds; 280.53o E. 51.47 pounds; 69.01o

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://www.slideshare.net/stootypal/concurrentforces1653276

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Once you have read the whole document there, you will very easily solve this problem

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2change to vectors and calculate...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Most probably the person is not acquainted to that method, that is why I have provided that link. Hope that will be helpful.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2we add the vectors right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2M<cos(t),sin(t)> for each vector

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.252<cos(100),sin(100)> = a 82<cos(190),sin(190)> = b 111<cos(310),sin(310)> = c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right I have that cause that's how my book sets it up... then I'm confused where to go from there cause I think my book skips a few steps explanation wise...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2i get a vetor of<18.4345,48.06> which is just a point from the origin

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2when we add all the vectors together from head to tail we get a new vector that points n the direction of the angle and with a new magnitude

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so that's what the <18.4345,48.06> is from....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2our new vector <x,y> has a magnitude of sqrt(x^2 + y^2) and a direction of tan^1(y/x) + pi

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the direction is 72.156?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2we add +pi because tan^1 only spits out angles in Q1 and Q4; so we no we need Q3 which will be 180 degrees from the tan^1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh.. ok? I'm kinda lost thought I was following you but I don't think I am any more

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2teh shaded area is the range that tan^1 operates in for define it as a function....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when you say so we now we need Q3 which will be 180 degrees from the tan^1 do I take tan(180) or tan^1(180)?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2our angle is in x,y..... which is Q3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2tan^1(our angles x and y) spits us out in Q1... add 180 to that to get our answer

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2200.985 is what I get

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2but let me recheck my fingers lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh wow I'm way off the problem is neither of our answers match up with theirs.... ugh this dang practice test is gonna be the death of me! lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2tan^1 spits out 20.9854

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2let me re check the vector addition.... i tend to mess that up alot :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2(52 * cos(100)) + (82 * cos(190)) + (111 * cos(310)) = 8.03584413 according to google

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2(52 * sin(100)) + (82 * sin(190)) + (111 * sin(310)) = 149.937061 google calculator again

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so I take the tan^1 of those and then add 180?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2((52 * sin(100)) + (82 * sin(190)) + (111 * sin(310)))  ((52 * cos(100)) + (82 * cos(190)) + (111 * cos(310))) = 18.6585328 so lets tan^1 that amount

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2the add 180 depends on where our angle is pointing; if its in Q1 or Q4 we are good; if not then add 180

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2with sin (+) and cos() we are in Q2 so add 180

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so if I add the 180 I get 93.06781973

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2.......thats what I get too. its not telling you any more info is it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Nope I can show you my answer choices...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2are your numbers right in the problem?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0jk i forgot I posted the answer choices with them lol no everything is right I took it right from my practice exam online....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2let me write up a quick javascript to help us..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ha ha ok just let me know thanks for helping me out so much!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2this is what i get, if its debbugged all the way

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it doesn't show my anything just blank what numbers should I plug in?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just kidding I'll plugg in my original numbers from the problem

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2im working and mags v1.3 :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ha ok....well idk I might just guess at it

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2....... either somethings missing in the problem like a gravity vector of a fr a friction vector.... or i forgot how to add :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ha ha no I think something is missing in the problem and it's just not written right on the review.... oh well thanks sorry I took so much of your time

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2'sok....try PIs way...and see if you ge tthe same results...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh Pi's way... wow I'm sorry you probably think i'm retarded or something lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2PI gave a website....you know, instead of conversing with you and such ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ha ha ya I read it lol my book gives me the same way we just tried it but I can try his way not sure if I understand it but I'll give it a shot thanks anyways!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.2woohoo....i got a 249 degrees
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