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anonymous

  • 5 years ago

Three forces with magnitudes of 52 pounds, 82 pounds, and 111 pounds act on an object at angles 100o, 190o, and 310o, respectively, with the positive x-axis. Find the magnitude and direction of the resultant force. Round answers to two decimal places. A. 33.13 pounds; 69.01o B. 51.47 pounds; 249.01o C. 33.13 pounds; 249.01o D. 73.18 pounds; 280.53o E. 51.47 pounds; 69.01o

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  1. anonymous
    • 5 years ago
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    http://www.slideshare.net/stootypal/concurrent-forces-1653276

  2. anonymous
    • 5 years ago
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    Once you have read the whole document there, you will very easily solve this problem

  3. amistre64
    • 5 years ago
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    change to vectors and calculate...

  4. anonymous
    • 5 years ago
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    Most probably the person is not acquainted to that method, that is why I have provided that link. Hope that will be helpful.

  5. amistre64
    • 5 years ago
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    we add the vectors right?

  6. amistre64
    • 5 years ago
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    |M|<cos(t),sin(t)> for each vector

  7. amistre64
    • 5 years ago
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    52<cos(100),sin(100)> = a 82<cos(190),sin(190)> = b 111<cos(310),sin(310)> = c

  8. anonymous
    • 5 years ago
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    right I have that cause that's how my book sets it up... then I'm confused where to go from there cause I think my book skips a few steps explanation wise...

  9. amistre64
    • 5 years ago
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    i get a vetor of<-18.4345,-48.06> which is just a point from the origin

  10. amistre64
    • 5 years ago
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    when we add all the vectors together from head to tail we get a new vector that points n the direction of the angle and with a new magnitude

  11. anonymous
    • 5 years ago
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    ok so that's what the <-18.4345,-48.06> is from....

  12. amistre64
    • 5 years ago
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    our new vector <x,y> has a magnitude of sqrt(x^2 + y^2) and a direction of tan^-1(y/x) + pi

  13. anonymous
    • 5 years ago
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    so the direction is 72.156?

  14. amistre64
    • 5 years ago
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    we add +pi because tan^-1 only spits out angles in Q1 and Q4; so we no we need Q3 which will be 180 degrees from the tan^-1

  15. anonymous
    • 5 years ago
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    oh.. ok? I'm kinda lost thought I was following you but I don't think I am any more

  16. amistre64
    • 5 years ago
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  17. amistre64
    • 5 years ago
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    teh shaded area is the range that tan^-1 operates in for define it as a function....

  18. anonymous
    • 5 years ago
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    when you say so we now we need Q3 which will be 180 degrees from the tan^-1 do I take tan(180) or tan^-1(180)?

  19. amistre64
    • 5 years ago
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    our angle is in -x,-y..... which is Q3

  20. anonymous
    • 5 years ago
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    ok

  21. amistre64
    • 5 years ago
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    tan^-1(our angles x and y) spits us out in Q1... add 180 to that to get our answer

  22. anonymous
    • 5 years ago
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    90.86?

  23. amistre64
    • 5 years ago
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    200.985 is what I get

  24. amistre64
    • 5 years ago
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    but let me recheck my fingers lol

  25. anonymous
    • 5 years ago
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    oh wow I'm way off the problem is neither of our answers match up with theirs.... ugh this dang practice test is gonna be the death of me! lol

  26. amistre64
    • 5 years ago
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    tan^-1 spits out 20.9854

  27. amistre64
    • 5 years ago
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    let me re check the vector addition.... i tend to mess that up alot :)

  28. amistre64
    • 5 years ago
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    (52 * cos(100)) + (82 * cos(190)) + (111 * cos(310)) = -8.03584413 according to google

  29. amistre64
    • 5 years ago
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    so thats our x coord

  30. amistre64
    • 5 years ago
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    (52 * sin(100)) + (82 * sin(190)) + (111 * sin(310)) = 149.937061 google calculator again

  31. anonymous
    • 5 years ago
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    so I take the tan^-1 of those and then add 180?

  32. amistre64
    • 5 years ago
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    ((52 * sin(100)) + (82 * sin(190)) + (111 * sin(310))) ------------------------------------------------ ((52 * cos(100)) + (82 * cos(190)) + (111 * cos(310))) = -18.6585328 so lets tan^-1 that amount

  33. anonymous
    • 5 years ago
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    ohhh I see

  34. anonymous
    • 5 years ago
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    -86.93218027

  35. amistre64
    • 5 years ago
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    the add 180 depends on where our angle is pointing; if its in Q1 or Q4 we are good; if not then add 180

  36. amistre64
    • 5 years ago
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    with sin (+) and cos(-) we are in Q2 so add 180

  37. anonymous
    • 5 years ago
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    so if I add the 180 I get 93.06781973

  38. amistre64
    • 5 years ago
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    .......thats what I get too. its not telling you any more info is it

  39. anonymous
    • 5 years ago
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    Nope I can show you my answer choices...

  40. amistre64
    • 5 years ago
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    are your numbers right in the problem?

  41. amistre64
    • 5 years ago
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    no typos?

  42. anonymous
    • 5 years ago
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    jk i forgot I posted the answer choices with them lol no everything is right I took it right from my practice exam online....

  43. amistre64
    • 5 years ago
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    let me write up a quick javascript to help us..

  44. anonymous
    • 5 years ago
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    ok

  45. amistre64
    • 5 years ago
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    almost done :)

  46. anonymous
    • 5 years ago
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    ha ha ok just let me know thanks for helping me out so much!

  47. amistre64
    • 5 years ago
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    this is what i get, if its debbugged all the way

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  48. anonymous
    • 5 years ago
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    it doesn't show my anything just blank what numbers should I plug in?

  49. anonymous
    • 5 years ago
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    just kidding I'll plugg in my original numbers from the problem

  50. amistre64
    • 5 years ago
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    ...... ha.....ha

  51. anonymous
    • 5 years ago
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    99.99?

  52. amistre64
    • 5 years ago
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    im working and mags v1.3 :)

  53. amistre64
    • 5 years ago
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    i know.......

  54. anonymous
    • 5 years ago
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    ha ok....well idk I might just guess at it

  55. amistre64
    • 5 years ago
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    ....... either somethings missing in the problem like a gravity vector of a fr a friction vector.... or i forgot how to add :)

  56. anonymous
    • 5 years ago
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    ha ha no I think something is missing in the problem and it's just not written right on the review.... oh well thanks sorry I took so much of your time

  57. amistre64
    • 5 years ago
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    'sok....try PIs way...and see if you ge tthe same results...

  58. anonymous
    • 5 years ago
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    say what?

  59. anonymous
    • 5 years ago
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    oh Pi's way... wow I'm sorry you probably think i'm retarded or something lol

  60. amistre64
    • 5 years ago
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    PI gave a website....you know, instead of conversing with you and such ;)

  61. anonymous
    • 5 years ago
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    ha ha ya I read it lol my book gives me the same way we just tried it but I can try his way not sure if I understand it but I'll give it a shot thanks anyways!

  62. amistre64
    • 5 years ago
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    woohoo....i got a 249 degrees

  63. amistre64
    • 5 years ago
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    its B

  64. anonymous
    • 5 years ago
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    Ha ha thank you!

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