## anonymous 5 years ago how do you solve y=e^(x+2)

1. mathmagician

$e ^{x}=y/(e ^{2}$. $x=\ln y+\ln(e ^{-2})=\ln y-2$

2. anonymous

lny = lne^(x+2) lny = (x+2)lne lny = x+2 x = lny -2

3. amistre64

it has many solutions; you slove it by graphing the plots on a peice of paper ...