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anonymous

  • 5 years ago

how do i find the slope intercept form of 3x-2y=-16?

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  1. amistre64
    • 5 years ago
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    solve for y

  2. amistre64
    • 5 years ago
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    3x-2y = -16 ; -3x -2y = -3x - 16 ; /-2 y = -3x/-2 -16/-2 y = (3/2)x +8

  3. anonymous
    • 5 years ago
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    what is the -3x for?

  4. anonymous
    • 5 years ago
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    is y=(3/2)x+8 the answer?

  5. amistre64
    • 5 years ago
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    when we have an equal sign in there that means that both saides are balanced; they weigh the same

  6. amistre64
    • 5 years ago
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    we have to keep them balanced so whatever we do to one side we have to do to the other....right

  7. amistre64
    • 5 years ago
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    how do we get y all by its little lonesome? first we have to -3x from it right?

  8. anonymous
    • 5 years ago
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    can you walk me through the rest of the problem?

  9. amistre64
    • 5 years ago
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    3x-3x -2y = -16-3x 0 -2y = -3x-16 -2y = -3x-16 do you agree?

  10. anonymous
    • 5 years ago
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    yes

  11. amistre64
    • 5 years ago
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    now we have a -2 stuck the the 'y'...and its stuck there by multiplication....we remove it by dividing. (-2/-2)y = (-3x/-2) -(16/-2) 1y = (3/2)x + 8 y = (3/2)x+8 ; do you agree?

  12. amistre64
    • 5 years ago
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    by doing albegraic techniques we simply change the way the problem looks; not the value of it...jus tthe shape of it

  13. anonymous
    • 5 years ago
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    yes! so y equals (3/2)x+8?

  14. amistre64
    • 5 years ago
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    unless you came to another conclsion without me...then yes, the final answer is the final answer :)

  15. anonymous
    • 5 years ago
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    thank you!

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