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\[x_t = 6(t-\sin(t)), y_t = 6(1-\cos(t))\]
-y+6=cost arccos(-y+6)=t x=6arccos(-y+6)-6sin(arccos(-y+6))
whats the problem?
are you trying to combine them into a funtion of x?
Thats probably what he wanted.
i wonder if t-sin(t) is a typo...
sorry guys, I was a bit busy
the thing is that t-sin(t) is not a typo and I know how to "eliminate t"
the problem is that a high school student asked me this question and I doubt that this is the answer that the school wants them to find
the solution of y is implicit and I find that a little weird
so I was wondering if anyone could figure out what is really going on
not without further information about the problem...
guessing is the best you could hope for..
okay... well thanks for trying guys. I'll give you medals for that.
Umm I have the same problem in my course book. What they want you to do is differentiate y and x with respect to t and then divide both the equations so you end up with \[dy/dx\]