anonymous
  • anonymous
Hi folks, I solved a 2nd order DE to obtain the general solution: y = A cos2x + B sin2x - (1/5) sin3x When I apply the two boundary conditions: y(-pi) = y(pi) and y'(-pi) = y'(pi) I get: A = A and B = B, what does this mean and have I applied the boundary conditions correctly??
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
myininaya
  • myininaya
yes for the first one I get A=A. when you get the same thing on both sides I believe that means A can be any constant let me look at the second one...
anonymous
  • anonymous
Thanks..
myininaya
  • myininaya
same thing for the second one i get B=B same case here B can be any constant

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Cheers, so having assertained that A and B are constants, how would I write that as an answer? Would I just write the general solution and say that A and B are constants???
myininaya
  • myininaya
yes thats what i would do
myininaya
  • myininaya
but any solution of that form is a solution
anonymous
  • anonymous
Excellent, thankyou :-)

Looking for something else?

Not the answer you are looking for? Search for more explanations.