Having trouble with another boundary condition question: y"+4y'+13y=0 Boundary condition: y'(0) = 0 and y'(pi) = 1 I get the general solution: y = e^(-2x) (Acos3x + Bsin3x) I think I may be doing this one wrong cause the last boundary condition doesn't work???

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Having trouble with another boundary condition question: y"+4y'+13y=0 Boundary condition: y'(0) = 0 and y'(pi) = 1 I get the general solution: y = e^(-2x) (Acos3x + Bsin3x) I think I may be doing this one wrong cause the last boundary condition doesn't work???

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

did you find the Lagrange multiplier?
Erm no?
i will scan something and see if it helps you k? just a sec

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Thanks again...
1 Attachment
do you see the two equations i got to solve for the constants
is that what you got?
i will try to do it after i finish eating
Yeh I got that, it's the y'(pi) bit i dont get, cheers enjoy your food...
I couldn't find the constants with those boundary conditions
any luck yuki?
So what would the solution look like?
i think the solution that satisfies both boundary conditions and the different equation is y=0 but wait 1 does not equal 0 so let me think about this some more it can't simply be there is no solution or can it...
I'm not sure, not come across a question where the boundary condition fails??
me either
Hmmm, I may have to investigate further, don't really know enough about these types of questions yet??
no solution it is possible
Do you think I should leave it as no solution then??
http://tutorial.math.lamar.edu/Classes/DE/BoundaryValueProblem.aspx it happened here
I'll check :-)
yes i would say no solution but show your work leading to that conclusion
i would say there is based on the boundary conditions there is no solution
Excellent, you've been ace, thanks...
thanks :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question