anonymous
  • anonymous
Having trouble with another boundary condition question: y"+4y'+13y=0 Boundary condition: y'(0) = 0 and y'(pi) = 1 I get the general solution: y = e^(-2x) (Acos3x + Bsin3x) I think I may be doing this one wrong cause the last boundary condition doesn't work???
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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yuki
  • yuki
did you find the Lagrange multiplier?
anonymous
  • anonymous
Erm no?
myininaya
  • myininaya
i will scan something and see if it helps you k? just a sec

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anonymous
  • anonymous
Thanks again...
myininaya
  • myininaya
1 Attachment
myininaya
  • myininaya
do you see the two equations i got to solve for the constants
myininaya
  • myininaya
is that what you got?
myininaya
  • myininaya
i will try to do it after i finish eating
anonymous
  • anonymous
Yeh I got that, it's the y'(pi) bit i dont get, cheers enjoy your food...
myininaya
  • myininaya
I couldn't find the constants with those boundary conditions
myininaya
  • myininaya
any luck yuki?
anonymous
  • anonymous
So what would the solution look like?
myininaya
  • myininaya
i think the solution that satisfies both boundary conditions and the different equation is y=0 but wait 1 does not equal 0 so let me think about this some more it can't simply be there is no solution or can it...
anonymous
  • anonymous
I'm not sure, not come across a question where the boundary condition fails??
myininaya
  • myininaya
me either
anonymous
  • anonymous
Hmmm, I may have to investigate further, don't really know enough about these types of questions yet??
myininaya
  • myininaya
no solution it is possible
anonymous
  • anonymous
Do you think I should leave it as no solution then??
myininaya
  • myininaya
http://tutorial.math.lamar.edu/Classes/DE/BoundaryValueProblem.aspx it happened here
anonymous
  • anonymous
I'll check :-)
myininaya
  • myininaya
yes i would say no solution but show your work leading to that conclusion
myininaya
  • myininaya
i would say there is based on the boundary conditions there is no solution
anonymous
  • anonymous
Excellent, you've been ace, thanks...
myininaya
  • myininaya
thanks :)

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