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anonymous

  • 5 years ago

Having trouble with another boundary condition question: y"+4y'+13y=0 Boundary condition: y'(0) = 0 and y'(pi) = 1 I get the general solution: y = e^(-2x) (Acos3x + Bsin3x) I think I may be doing this one wrong cause the last boundary condition doesn't work???

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  1. Yuki
    • 5 years ago
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    did you find the Lagrange multiplier?

  2. anonymous
    • 5 years ago
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    Erm no?

  3. myininaya
    • 5 years ago
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    i will scan something and see if it helps you k? just a sec

  4. anonymous
    • 5 years ago
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    Thanks again...

  5. myininaya
    • 5 years ago
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  6. myininaya
    • 5 years ago
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    do you see the two equations i got to solve for the constants

  7. myininaya
    • 5 years ago
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    is that what you got?

  8. myininaya
    • 5 years ago
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    i will try to do it after i finish eating

  9. anonymous
    • 5 years ago
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    Yeh I got that, it's the y'(pi) bit i dont get, cheers enjoy your food...

  10. myininaya
    • 5 years ago
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    I couldn't find the constants with those boundary conditions

  11. myininaya
    • 5 years ago
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    any luck yuki?

  12. anonymous
    • 5 years ago
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    So what would the solution look like?

  13. myininaya
    • 5 years ago
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    i think the solution that satisfies both boundary conditions and the different equation is y=0 but wait 1 does not equal 0 so let me think about this some more it can't simply be there is no solution or can it...

  14. anonymous
    • 5 years ago
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    I'm not sure, not come across a question where the boundary condition fails??

  15. myininaya
    • 5 years ago
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    me either

  16. anonymous
    • 5 years ago
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    Hmmm, I may have to investigate further, don't really know enough about these types of questions yet??

  17. myininaya
    • 5 years ago
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    no solution it is possible

  18. anonymous
    • 5 years ago
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    Do you think I should leave it as no solution then??

  19. myininaya
    • 5 years ago
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    http://tutorial.math.lamar.edu/Classes/DE/BoundaryValueProblem.aspx it happened here

  20. anonymous
    • 5 years ago
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    I'll check :-)

  21. myininaya
    • 5 years ago
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    yes i would say no solution but show your work leading to that conclusion

  22. myininaya
    • 5 years ago
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    i would say there is based on the boundary conditions there is no solution

  23. anonymous
    • 5 years ago
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    Excellent, you've been ace, thanks...

  24. myininaya
    • 5 years ago
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    thanks :)

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