Factor Completely: 18x2 - 32y2

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Factor Completely: 18x2 - 32y2

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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-4 (8 y^2-9)
Or 36-32 y^2 2 (3 sqrt(2)-4 y) (4 y+3 sqrt(2))
a) 2(9x2 - 16y2) b) 2(3x + 4y)(3x - 4y) c) (9x - 16y)(2x + 2y) d) Can't be factored.

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Other answers:

a
a is identical to my first reply
b. if you multiply out b you get the result.
is it a or b
http://www.wolframalpha.com/input/?i=factor18x2+-+32y2
http://www.wolframalpha.com/input/?i=2%289x2+-+16y2%29
they are the same
It's b. 9x^2 - 16y^2 is the difference of two squares. (3x+4y)(3x-4y)
but because the question asks you to factor completely you want b.
the original expression is 18x2 - 32y2
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so the first step is to factor out the 2: 2(9x^2 - 16y^2) and then factor the second part as I mentioned above.
ah I see what you did gotcha. Yes B is more accurate.
I didn't simplify the first factorization I gave correctly.
-4 (8 y^2-9) and 2(3x + 4y)(3x - 4y) are the same

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