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ok you see x=-5y-7
plug that x into the other equation
4(-5y-7)+5y=17

now solve for y

first you would distribute 4 right?? omg this is highschool stuff and im only in middle school! -_-

yes

-20y-28+5y=17
now what

plus 28 on both sides. meaning you wud cancel out -28 and add 28 to 17

wait i got
-25y - 28 = 17

i combined like terms.

then i ended up with -25y = 45

-15y=45
y=-3

ahhh thanks. my bad.

then what do i do? i have to give the ordered pairs.

what is x if y=-3

remember x=-5y-7 and we know y=-3 so x=?

yeah. so x = 8 ! omggg

you've made my life so much easier

my teacher taught it to me in an impossible way. thank you so much.

you taught me in a different way.

the ordered pair (x,y)=(8,-3)

yeah. i got it! thank you so much!

there are other ways to solve this types
i like substitution the most thats what we did above

my teacher told me to put it in y=mx + b form. but i didnt know how to do that.

solve both of them for y

what do you mean?

this one seems more complicated.

wait, can you see if im right on this other one i did.

y= 1/2x - 2 ( a half times x minus 2 )
y= -3x +5

i got (1, -2 )

i plotted these equations and choose the ordered pair below where these lines intersect.

x/2-2=-3x+5
x-4=-6x+10
7x=14
x=2
so y=-3(2)+5=-1
(x,y)=(2,-1)

where did x/2 come from?

isn't that 1/2 * x up there?

nevermind. i got it.

can you explain to me how you got x-4 = -6x + 10 what did you multiply?

i just got rid of the fractions by multiplying both sides by 2

hmmm. so you multiplied the reciprocal of x/2

which is 2/x then you multiplied that by -2 and -3 and positive 5.

and thats how you got your answer right?

no i multiplied by 2 not 2/x

2(x/2)-2(2)=2(-3x)+2(5)
x-4=-6x+10

gotcha

thank you so much!

np

can you please help me with another one?

im not good in algebra 1 im only in 8th grade and this is hs stuff.

hello.