give the ordered pair that satisfies the system of equations below... x= -5y-7 4x + 5y = 17 someone please help me! i really dont understand it. can you please indicate me what to do!

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give the ordered pair that satisfies the system of equations below... x= -5y-7 4x + 5y = 17 someone please help me! i really dont understand it. can you please indicate me what to do!

Mathematics
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ok you see x=-5y-7 plug that x into the other equation 4(-5y-7)+5y=17
now solve for y
first you would distribute 4 right?? omg this is highschool stuff and im only in middle school! -_-

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Other answers:

yes
-20y-28+5y=17 now what
plus 28 on both sides. meaning you wud cancel out -28 and add 28 to 17
wait i got -25y - 28 = 17
i combined like terms.
then i ended up with -25y = 45
-15y=45 y=-3
ahhh thanks. my bad.
then what do i do? i have to give the ordered pairs.
what is x if y=-3
remember x=-5y-7 and we know y=-3 so x=?
yeah. so x = 8 ! omggg
you've made my life so much easier
my teacher taught it to me in an impossible way. thank you so much.
you taught me in a different way.
the ordered pair (x,y)=(8,-3)
yeah. i got it! thank you so much!
there are other ways to solve this types i like substitution the most thats what we did above
my teacher told me to put it in y=mx + b form. but i didnt know how to do that.
solve both of them for y
what do you mean?
x=-5y-7 add 7 to both sides x+7=-5y now divide by -5 on both sides (x+7)/(-5)=y y=x/(-5)+7/(-5) y=-x/5-7/5 the other equation...
4x+5y=17 solve for y we subtract 4x on both sides 5y=-4x+17 now divide by 5 y=(-4x+17)/5 y=-4x/5+17/5
to see where the lines intersect set them equal after putting both in y=mx+b form so we have -x/5-7/5=-4x/5+17/5 we can get rid of the fractions by multiplying both sides by 5 so we have -x-7=-4x+17
this one seems more complicated.
solve the above this equation for x by first add 4x on both sides 3x-7=17 adding 7 3x=24 x=8 to find out what y is we just plug into either y=-4x/5+17/5 or y=-x/5-7/5 so if x=8, y=-8/5-7/5=-15/5=-3 so the ordered pair is (x,y)=(8,-3)
ahhh. but i like the other way better. this one seems like more work. but i find the other one easier.
wait, can you see if im right on this other one i did.
y= 1/2x - 2 ( a half times x minus 2 ) y= -3x +5
i got (1, -2 )
i plotted these equations and choose the ordered pair below where these lines intersect.
x/2-2=-3x+5 x-4=-6x+10 7x=14 x=2 so y=-3(2)+5=-1 (x,y)=(2,-1)
where did x/2 come from?
isn't that 1/2 * x up there?
nevermind. i got it.
can you explain to me how you got x-4 = -6x + 10 what did you multiply?
i just got rid of the fractions by multiplying both sides by 2
hmmm. so you multiplied the reciprocal of x/2
which is 2/x then you multiplied that by -2 and -3 and positive 5.
and thats how you got your answer right?
no i multiplied by 2 not 2/x
2(x/2)-2(2)=2(-3x)+2(5) x-4=-6x+10
gotcha
thank you so much!
np
can you please help me with another one?
im not good in algebra 1 im only in 8th grade and this is hs stuff.
hello.

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